从ASP发送推送通知.. NET到Android应用程序
本文关键字:Android 应用程序 NET ASP 通知 | 更新日期: 2023-09-27 18:06:28
我想从我的ASP发送一个小的推送通知。Post方法到我的简单Android应用程序。以下是我所有的尝试和重新搜索。
我正在使用谷歌云消息服务发送通知到应用程序。我的应用程序接收它的名称值对。我还在这里给出了服务器代码的Java版本和我的Post方法中的c#实现。但是我的方法抛出一个异常Android应用程序中的"Exception occurred with Error as(15913): println needs a message"
服务器部分的工作Java代码如下:-
public void sendmessage2Device(View v,String regisID,String msg1,String msg2) {
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(
"https://android.googleapis.com/gcm/send");
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("registration_id",regisID));
nameValuePairs.add(new BasicNameValuePair("data1",msg1));
nameValuePairs.add(new BasicNameValuePair("data2", msg2));
post.setHeader("Authorization","key=AIzaSyBB6igK9sYYBTSIly6SRUHFVexeOa_7FuM");
post.setHeader("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8");
post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = client.execute(post);
InputStreamReader inputst = new InputStreamReader(response.getEntity().getContent());
BufferedReader rd = new BufferedReader(inputst);
String line = "";
while ((line = rd.readLine()) != null) {
Log.e("HttpResponse", line);
String s = line.substring(0);
Log.i("GCM response",s);
//Toast.makeText(v.getContext(), s, Toast.LENGTH_LONG).show();
}
} catch (IOException e) {
e.printStackTrace();
}
同样,我的c#代码在ASP。. NET WEB API如下:
public String Post([FromBody]TransactionDetails value)
{
try
{
WebClient toGCM = new WebClient();
toGCM.Headers.Add("ContentType:");
toGCM.Headers["ContentType"] = "application/x-www-form-urlencoded; charset=UTF-8";
//HttpWebRequest toGCM = (HttpWebRequest)WebRequest.Create("https://android.googleapis.com/gcm/send");
//toGCM.ContentType = "application/x-www-form-urlencoded; charset=UTF-8";
toGCM.Headers.Add("Accept:");
toGCM.Headers["Accept"]= "Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.114 Safari/537.36";
//toGCM.Accept = "application/json, text/javascript, */*; q=0.01";
toGCM.Headers.Add("UserAgent:") ;
toGCM.Headers["UserAgent"]= "Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.114 Safari/537.36";
toGCM.Headers.Add("Authorization:");
toGCM.Headers["Authorization"] = "key=AIzaSyCoxjeOGi_1ss2TeShDcoYbNcPU9_0J_TY";
//String DatatoClient = "ToAccountNumber=" + value.ToAccountNumber + "&Amount=" + value.Amount;
NameValueCollection postFieldNameValue = new NameValueCollection();
postFieldNameValue.Add("registration_id", "APA91bHzO52-3TsEIMV3RXi45ICIo9HOe1ospPl3gRYwAAw59ATHvadGPZN86heHOQJNU8syju-yD9UQqSgkZOqllGi5AoSPMRRuw3RYhgApflr0abLoAh2GWFQCZgToG_aM0rOg0lBV8osz6ZMtP1JBF1S9_DiWiqKRT5WL6qFz4PqyE0jCHsE");
postFieldNameValue.Add("Account", value.ToAccountNumber.ToString());
postFieldNameValue.Add("Amount", value.Amount.ToString());
byte[] responseArray = toGCM.UploadValues("https://android.googleapis.com/gcm/send", postFieldNameValue);
String S=Encoding.ASCII.GetString(responseArray);
return S;
}
catch (Exception e)
{
Console.WriteLine("Exception Occured in Post Method on Web Server as:{0}", e.Message);
return e.Message;
}
}
在Android APP中,我有以下LOC for Receiver…
public void onReceive(Context context, Intent intent) {
try {
String action = intent.getAction();
if (action.equals("com.google.android.c2dm.intent.REGISTRATION"))
{
String registrationId = intent.getStringExtra("registration_id");
Log.i("Received the Registration Id as ",registrationId);
String error = intent.getStringExtra("error");
String unregistered = intent.getStringExtra("unregistered");
}
else if (action.equals("com.google.android.c2dm.intent.RECEIVE"))
{
Log.i("In the RECEIVE Method ",intent.getStringExtra("Account"));
String Account = intent.getStringExtra("Account");
String Amount = intent.getStringExtra("Amount");
Log.i("Received Account as ",Account);
Log.i("Received Amount as ",Amount);
}
}
catch(Exception e)
{
Log.i("Exception Occured with Error as ",e.getMessage());
}
finally
{
}
我对Android开发非常陌生,这是我的第一个Helloworld Android应用程序。谁能告诉我我做错了什么,为什么异常被抛出,以及如何纠正它?
经过大量的研究发现了这个问题。我假定LOG . I()也在内部使用println将消息打印到LOG。由于GCM没有推送我的客户端代码正在寻找的任何数据,因此它抛出了一个异常。把它放在一边,我得到了推送通知工作,这是我学到的,因为它可能对有同样问题的其他人有用。
- GCM使用JSON接收和推送通知到设备
-
GCM接收的JSON具有如下所示的预定义格式
{数据:{账号:您的号码,金额:您的金额},registration_ids (id1, id2 id3…):}
PFB是我ASP的代码。. NET服务器端和客户端接收器
服务器端: -
public String Post([FromBody]TransactionDetails value, HttpRequestMessage receivedReq)
{
try
{
var httpWebRequest = (HttpWebRequest)WebRequest.Create("https://android.googleapis.com/gcm/send");
httpWebRequest.ContentType = "application/json; charset=UTF-8";
httpWebRequest.Method = "POST";
httpWebRequest.Headers.Add("Authorization", "key=AIzaSyBs_eh4nNVaJl3FjQ_ZC72ZZ6uQ2F8r8W4");
String result = "";
String yourresp = "<html><head><title>Response from Server</title></head><body>";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
string json = "{'"data'":" +"{'"Amount'":"+value.Amount+","+
"'"Account'":"+value.ToAccountNumber+"}"+","+
"'"registration_ids'":[" + "'""+value.RegID +"'"]}";
streamWriter.Write(json);
streamWriter.Flush();
streamWriter.Close();
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
result = streamReader.ReadToEnd();
}
}
DialogResult result1 = MessageBox.Show("Server sent the details to your phone, Check and Confirm to Continue or Not", "Important Information",MessageBoxButtons.YesNo);
if (result1.ToString().Contains("Yes"))
{
WriteAccountNumber(value.ToAccountNumber, value.Amount);
yourresp += "<h1>The Transaction was Successful</h1>";
}
else
{
yourresp += "<h1>The Transaction was NOT Successful</h1>";
}
yourresp += "</body></html>";
return yourresp;
}
catch (Exception e)
{
Console.WriteLine("Exception Occured in Post Method on Web Server as:{0}", e.Message);
return e.Message;
}
}
在Android App的客户端如下:-
else if (action.equals("com.google.android.c2dm.intent.RECEIVE"))
{
//Log.i("Message Received","Before Scheme");
String Account=intent.getStringExtra("Account");
String Amount=intent.getStringExtra("Amount");
Toast.makeText(context, "Your Transaction Details Received by the Server are...'n'nAccount="+Account+"'nAmount="+Amount, Toast.LENGTH_LONG).show();
Log.i("Account=",Account);
Log.i("Amount=",Amount);
}
所以,现在我只想知道如何在警报或任何类型的对话框中显示收到的通知与一个OK按钮。谁能帮我什么类和如何使用它在我的应用程序显示给用户?如果应用程序不是活动的,它可以在通知栏中显示,否则需要弹出一个OK按钮。
谢谢,