在php中从c#接收图像
本文关键字:图像 php 中从 | 更新日期: 2023-09-27 18:06:39
我使用下面的代码将一个图像从桌面应用程序发送到服务器上的php文件:
// Create a request using a URL that can receive a post.
WebRequest request = WebRequest.Create("http://example.com/img.php");
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
string postData = "hello";
byte[] byteArray = ImageToByte(image);//Encoding.UTF8.GetBytes (postData);
byteArray = Encoding.UTF8.GetBytes(postData);
// Set the ContentType property of the WebRequest.
request.ContentType = "application/x-www-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.
Stream dataStream = request.GetRequestStream ();
// Write the data to the request stream.
dataStream.Write (byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close ();
// Get the response.
WebResponse response = request.GetResponse ();
// Display the status.
Console.WriteLine (((HttpWebResponse)response).StatusDescription);
// Get the stream containing content returned by the server.
dataStream = response.GetResponseStream ();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader (dataStream);
// Read the content.
string responseFromServer = reader.ReadToEnd ();
// Display the content.
Console.WriteLine (responseFromServer);
// Clean up the streams.
reader.Close ();
dataStream.Close ();
response.Close ();
我应该在php中使用什么函数来接收图像文件?
由于您没有形成标准化的帖子,因此您需要直接从php输入中读取。
file_get_contents("php://input");
如果你的c#代码产生一个有效的post请求,你应该能够在PHP中从全局$_POST
数组中获取它