返回泛型对象类型
本文关键字:类型 对象 泛型 返回 | 更新日期: 2023-09-27 18:06:52
我们在GitHub Gist上的完整代码,我只包括我认为需要显示问题的部分。
Execute method:
public object Execute()
{
var request = createWebRequest();
request.Method = this.Method;
applyPostData(ref request);
request.ContentType = "application/json";
request.UserAgent = "generic-http-dotnet-client/3.5/v1 (gzip)";
var response = (HttpWebResponse)request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
try
{
return JsonConvert.DeserializeObject(responseString);
}
catch (Exception)
{
return new HttpResponse { message = responseString };
}
}
好吧,这是可行的。然而,我希望能够做的是,在方法被调用后,将其转换为适当的对象类型。
var response = (MetaDataResponse)request.Execute();
我知道应该有一些方法可能使用泛型(野生猜测)我json DeserializeObject的响应和返回它?
我最终将execute方法的返回类型更改为字符串,并这样做。
public class MetaDataRequest : HttpRequestBase
{
public MetaDataResponse MetaDataItems { get; private set; }
public MetaDataRequest() : base(new Uri("https://www.googleapis.com/analytics/v3/metadata/ga/columns"), "GET")
{
this.addParameter("key", "xxxx");
var response = this.Execute();
try
{
MetaDataItems = JsonConvert.DeserializeObject<MetaDataResponse>(response);
}
catch (Exception)
{
var resultsx = new HttpResponse { message = response };
}
}
}
这是有效的,但对我来说有点乱。注意这个项目是。. Net framework 3.5,我不能改变它。你可以随意添加任何你能想到的标签
使用泛型类MetaDataRequest
class MetadataRequest<T>:HttpRequestBase
{
public T Execute()
{
var request = createWebRequest();
request.Method = this.Method;
applyPostData(ref request);
request.ContentType = "application/json";
request.UserAgent = "generic-http-dotnet-client/3.5/v1 (gzip)";
var response = (HttpWebResponse)request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
return JsonConvert.DeserializeObject<T>(responseString);
}
}
然后,要获得对象,可以像这样调用方法:
MetadataResponse responseObject = (new MetadataRequest<MetadataResponse>()).Execute();
在这种情况下,您可以捕获.Execute()抛出的异常,因为它只能返回null或t类型的实例。
编辑:您也可以通过遵循Jeremy Holovacs的回答来使用通用方法。
首先,要点是不处理它的一次性用品,这是相当草率的。我建议这样做:
public T Execute<T>()
{
var request = createWebRequest();
request.Method = this.Method;
applyPostData(ref request);
request.ContentType = "application/json";
request.UserAgent = "generic-http-dotnet-client/3.5/v1 (gzip)";
using(var response = (HttpWebResponse)request.GetResponse())
using(var stream = response.GetResponseStream())
using(var reader = new StreamReader(stream))
{
try
{
var responseString = reader.ReadToEnd();
return JsonConvert.DeserializeObject<T>(responseString);
}
catch (Exception ex)
{
//log something with ex
return default(T);
}
}
}