双向绑定不能在一个方向上工作
本文关键字:一个 方向 工作 绑定 不能 | 更新日期: 2023-09-27 18:07:57
我创建了一个非常简单的例子来显示我的问题。也许是我想错了。
我想在我的TreeView中选择一个项目-我想在视图中看到它(蓝色背景)。
为了实现TwoWayBinding,我使用以下行为:数据绑定到WPF树视图中的SelectedItem
public class BindableSelectedItemBehavior : Behavior<TreeView>
{
#region SelectedItem Property
public object SelectedItem
{
get { return (object)GetValue(SelectedItemProperty); }
set { SetValue(SelectedItemProperty, value); }
}
public static readonly DependencyProperty SelectedItemProperty =
DependencyProperty.Register("SelectedItem", typeof(object), typeof(BindableSelectedItemBehavior), new UIPropertyMetadata(null, OnSelectedItemChanged));
private static void OnSelectedItemChanged(DependencyObject sender, DependencyPropertyChangedEventArgs e)
{
var item = e.NewValue as TreeViewItem;
if (item != null)
{
item.SetValue(TreeViewItem.IsSelectedProperty, true);
}
}
#endregion
protected override void OnAttached()
{
base.OnAttached();
this.AssociatedObject.SelectedItemChanged += OnTreeViewSelectedItemChanged;
}
protected override void OnDetaching()
{
base.OnDetaching();
if (this.AssociatedObject != null)
{
this.AssociatedObject.SelectedItemChanged -= OnTreeViewSelectedItemChanged;
}
}
private void OnTreeViewSelectedItemChanged(object sender, RoutedPropertyChangedEventArgs<object> e)
{
this.SelectedItem = e.NewValue;
}
}
但是如果我点击一个项目它不会进入OnSelectedItemChanged
的if因为e.newValue as TreeViewItem
是null
我的XAML很简单:
<StackPanel>
<TreeView xmlns:i="clr-namespace:System.Windows.Interactivity;assembly=System.Windows.Interactivity"
ItemsSource="{Binding Items}">
<i:Interaction.Behaviors>
<local:BindableSelectedItemBehavior
SelectedItem="{Binding Item}" />
</i:Interaction.Behaviors>
<TreeView.ItemTemplate>
<HierarchicalDataTemplate>
<TextBlock Text="{Binding Text}"/>
</HierarchicalDataTemplate>
</TreeView.ItemTemplate>
</TreeView>
<TextBox Text="{Binding Item.Text}"/>
</StackPanel>
谢谢大家!
为了方便起见,下面是OP和ghrod的答案的最终解决方案:
namespace MyPoject.Behaviors
{
using System.Windows;
using System.Windows.Controls;
using System.Windows.Interactivity;
public class BindableSelectedItemBehavior : Behavior<TreeView>
{
#region SelectedItem Property
public object SelectedItem
{
get { return (object)GetValue(SelectedItemProperty); }
set { SetValue(SelectedItemProperty, value); }
}
public static readonly DependencyProperty SelectedItemProperty =
DependencyProperty.Register(
nameof(SelectedItem),
typeof(object),
typeof(BindableSelectedItemBehavior),
new FrameworkPropertyMetadata(null,
FrameworkPropertyMetadataOptions.BindsTwoWayByDefault,
OnSelectedItemChanged));
static void OnSelectedItemChanged(DependencyObject sender,
DependencyPropertyChangedEventArgs e)
{
var behavior = (BindableSelectedItemBehavior)sender;
var generator = behavior.AssociatedObject.ItemContainerGenerator;
if (generator.ContainerFromItem(e.NewValue) is TreeViewItem item)
item.SetValue(TreeViewItem.IsSelectedProperty, true);
}
#endregion
protected override void OnAttached()
{
base.OnAttached();
AssociatedObject.SelectedItemChanged += OnTreeViewSelectedItemChanged;
}
protected override void OnDetaching()
{
base.OnDetaching();
if (this.AssociatedObject != null)
AssociatedObject.SelectedItemChanged -= OnTreeViewSelectedItemChanged;
}
void OnTreeViewSelectedItemChanged(object sender,
RoutedPropertyChangedEventArgs<object> e) =>
SelectedItem = e.NewValue;
}
}
TreeView
的SelectedItem
属性在您的情况下不返回TreeViewItem
。它从绑定的Items
集合中返回当前选定的项目。要从SelectedItem
获得TreeViewItem
,您需要在这里使用ItemContainerGenerator
:
private static void OnSelectedItemChanged(DependencyObject sender,
DependencyPropertyChangedEventArgs e)
{
var behavior = (BindableSelectedItemBehavior)sender;
var generator = behavior.AssociatedObject.ItemContainerGenerator;
var item = generator.ContainerFromItem(e.NewValue) as TreeViewItem;
if (item != null)
{
item.SetValue(TreeViewItem.IsSelectedProperty, true);
}
}
你的OnSelectedItemChanged只会传递一个类型为TreeViewItem的对象,如果你的实际模型对象是类型为TreeViewItem,这不会是99%的情况下。相反,你必须从模型对象中检索TreeViewItem,但是如果节点当前是折叠的,它将不可用,这使得选择折叠的节点非常重要。
我已经在我的博客中非常彻底地解释了这一点,包括这里的代码示例