向BeginInvoke()传递多个参数
本文关键字:参数 BeginInvoke | 更新日期: 2023-09-27 18:08:25
我有简单的逻辑。
public static void NotifyAboutNewJob(int jobId, bool forceSending = false)
{
Action<int> notifier = SendAppleNotifications;
notifier.BeginInvoke(jobId, null, null);
}
方法sendapplenotifations有一个参数,很容易传递给BeginInvoke
。现在我添加了第二个参数forceSending
。问题是,我不知道如何将其传递到BeginInvoke
。
我应该把它作为第三个参数传递给object
吗?
private static void SendAppleNotifications(int jobId, bool forceSending = false){...}
或者答案是:
Action<int, bool> notifier = SendAppleNotifications;
notifier.BeginInvoke(jobId, forceSending, null, null);
将Action<int>
更改为Action<int, bool>
Action<int, bool> notifier = SendAppleNotifications;
notifier.BeginInvoke(jobId, forceSending, null, null); // You can now pass true or false as 2nd parameter.