优化/重写LINQ查询与GROUP BY和COUNT
本文关键字:GROUP BY COUNT 查询 重写 LINQ 优化 | 更新日期: 2023-09-27 17:50:49
我试图在以下数据集上获得按名称分组的唯一foo和bar的计数。
Id | IsActive | Name | Foo | Bar
1 | 1 | A | 11 | null
2 | 1 | A | 11 | null
3 | 1 | A | null | 123
4 | 1 | B | null | 321
我期望上述数据的结果是:
Expected:
A = 2;
B = 1;
我尝试按名称,Foo,Bar分组,然后再按名称分组,计数以获得"行"计数。但这并没有给我正确的结果。(或者ToDictionary扔了一个重复的键,我玩了很多,所以不太记得了)
db.MyEntity
.Where(x => x.IsActive)
.GroupBy(x => new { x.Name, x.Foo, x.Bar })
.GroupBy(x => new { x.Key.Name, Count = x.Count() })
.ToDictionary(x => x.Key, x => x.Count);
所以我想出了这个LINQ查询。但是它相当慢。
db.MyEntity
.Where(x => x.IsActive)
.GroupBy(x => x.Name)
.ToDictionary(x => x.Key,
x =>
x.Where(y => y.Foo != null).Select(y => y.Foo).Distinct().Count() +
x.Where(y => y.Bar != null).Select(y => y.Bar).Distinct().Count());
我如何优化它?
这是要参考的实体
public class MyEntity
{
public int Id { get; set; }
public bool IsActive { get; set; }
public string Name { get; set; }
public int? Foo { get; set; }
public int? Bar { get; set; }
}
编辑
我也试过这个查询
db.MyEntity
.Where(x => x.IsActive)
.GroupBy(x => new { x.Name, x.Foo, x.Bar })
.GroupBy(x => x.Key.Name)
.ToDictionary(x => x.Key, x => x.Count());
但是这会抛出一个超时异常:(
查询效率极低,因为您在客户端做了很多工作(构建字典所涉及的所有工作),而无法使用数据库进行预测。这是一个问题,因为数据库(特别是如果这些值被索引)可以比客户端更快地完成这项工作,也因为在数据库上进行预测涉及到通过网络发送的数据要少得多。
所以在分组数据之前,简单地做你的预测。
var activeItems = db.MyEntity.Where(x => x.IsActive);
var query = activeItems.Select(x => new { Name, Value = x.Foo}).Distinct()
.Concat(activeItems.Select(x => new { Name, Value = x.Bar}).Distinct())
.Where(x => x != null)
.GroupBy(pair => pair.Name)
.Select(group => new { group.Key, Count = Group.Count()})
.ToDictionary(pair => pair.Key, pair => pair.Count);
您的目标是生成以下查询:
select Name, count(distinct Foo) + count(distinct Bar)
from myEntity
where IsActive = 1
group by Name
这是获得所需内容的最小查询。但是LINQ似乎把一切都尽可能地复杂化了:)
您的目标是在数据库级别尽可能多地完成任务。现在您的查询被翻译为:
SELECT
[Project2].[C1] AS [C1],
[Project2].[Name] AS [Name],
[Project2].[C2] AS [C2],
[Project2].[id] AS [id],
[Project2].[IsActive] AS [IsActive],
[Project2].[Name1] AS [Name1],
[Project2].[Foo] AS [Foo],
[Project2].[Bar] AS [Bar]
FROM ( SELECT
[Distinct1].[Name] AS [Name],
1 AS [C1],
[Extent2].[id] AS [id],
[Extent2].[IsActive] AS [IsActive],
[Extent2].[Name] AS [Name1],
[Extent2].[Foo] AS [Foo],
[Extent2].[Bar] AS [Bar],
CASE WHEN ([Extent2].[id] IS NULL) THEN CAST(NULL AS int) ELSE 1 END AS [C2]
FROM (SELECT DISTINCT
[Extent1].[Name] AS [Name]
FROM [dbo].[SomeTable] AS [Extent1]
WHERE [Extent1].[IsActive] = 1 ) AS [Distinct1]
LEFT OUTER JOIN [dbo].[SomeTable] AS [Extent2] ON ([Extent2].[IsActive] = 1) AND ([Distinct1].[Name] = [Extent2].[Name])
) AS [Project2]
ORDER BY [Project2].[Name] ASC, [Project2].[C2] ASC
它从数据库中选择所有内容,并在应用层进行分组,这是低效的。
@Servy的查询:
var activeItems = db.MyEntity.Where(x => x.IsActive);
var query = activeItems.Select(x => new { Name, Value = x.Foo}).Distinct()
.Concat(activeItems.Select(x => new { Name, Value = x.Bar}).Distinct())
.Where(x => x != null)
.GroupBy(pair => pair.Name)
.Select(group => new { group.Key, Count = Group.Count()})
.ToDictionary(pair => pair.Key, pair => pair.Count);
被翻译成:
SELECT
1 AS [C1],
[GroupBy1].[K1] AS [C2],
[GroupBy1].[A1] AS [C3]
FROM ( SELECT
[UnionAll1].[Name] AS [K1],
COUNT(1) AS [A1]
FROM (SELECT
[Distinct1].[Name] AS [Name]
FROM ( SELECT DISTINCT
[Extent1].[Name] AS [Name],
[Extent1].[Foo] AS [Foo]
FROM [dbo].[SomeTable] AS [Extent1]
WHERE ([Extent1].[IsActive] = 1) AND ([Extent1].[Foo] IS NOT NULL)
) AS [Distinct1]
UNION ALL
SELECT
[Distinct2].[Name] AS [Name]
FROM ( SELECT DISTINCT
[Extent2].[Name] AS [Name],
[Extent2].[Bar] AS [Bar]
FROM [dbo].[SomeTable] AS [Extent2]
WHERE ([Extent2].[IsActive] = 1) AND ([Extent2].[Bar] IS NOT NULL)
) AS [Distinct2]) AS [UnionAll1]
GROUP BY [UnionAll1].[Name]
) AS [GroupBy1]
好多了。
我已经试过了:
var activeItems = (from o in db.SomeTables
where o.IsActive
group o by o.Name into gr
select new { gr.Key, cc = gr.Select(c => c.Foo).Distinct().Count(c => c != null) +
gr.Select(c => c.Bar).Distinct().Count(c => c != null) }).ToDictionary(c => c.Key);
翻译成:
SELECT
1 AS [C1],
[Project5].[Name] AS [Name],
[Project5].[C1] + [Project5].[C2] AS [C2]
FROM ( SELECT
[Project3].[Name] AS [Name],
[Project3].[C1] AS [C1],
(SELECT
COUNT(1) AS [A1]
FROM ( SELECT DISTINCT
[Extent3].[Bar] AS [Bar]
FROM [dbo].[SomeTable] AS [Extent3]
WHERE ([Extent3].[IsActive] = 1) AND ([Project3].[Name] = [Extent3].[Name]) AND ([Extent3].[Bar] IS NOT NULL)
) AS [Distinct3]) AS [C2]
FROM ( SELECT
[Distinct1].[Name] AS [Name],
(SELECT
COUNT(1) AS [A1]
FROM ( SELECT DISTINCT
[Extent2].[Foo] AS [Foo]
FROM [dbo].[SomeTable] AS [Extent2]
WHERE ([Extent2].[IsActive] = 1) AND ([Distinct1].[Name] = [Extent2].[Name]) AND ([Extent2].[Foo] IS NOT NULL)
) AS [Distinct2]) AS [C1]
FROM ( SELECT DISTINCT
[Extent1].[Name] AS [Name]
FROM [dbo].[SomeTable] AS [Extent1]
WHERE [Extent1].[IsActive] = 1
) AS [Distinct1]
) AS [Project3]
) AS [Project5]
与第二版基本相同,但没有联合。
结论:
我将创建一个视图,并将其导入模型,如果表是相当大的,性能是至关重要的。否则,坚持第三版或第二版@Servy。当然应该测试性能
我认为你可以稍微修改一下你的初始查询,以得到你想要的:
db.MyEntity
.Where(x => x.IsActive)
.GroupBy(x => new { x.Name, x.Foo, x.Bar })
.GroupBy(x => x.Key.Name)
.ToDictionary(x => x.Key, x => x.Count());
当您将Count()
添加到第二个分组时,您正在计算由三部分组成的键的重复值。您只希望计算每个由三部分组成的键的不同值,因此在按Name
分组的之后计算。
只有关于问题的建议可以不使用DISTINCT以获得更好的性能。使用分组。
请查看此链接