LINQ 组嵌套列表以重构数据
本文关键字:重构 数据 列表 嵌套 LINQ | 更新日期: 2024-11-08 23:25:45
我有一个嵌套列表,其中包含从服务作为 JSON 传递的自定义对象,我需要将其重组为新对象。下面是嵌套列表包含的对象:
public class Alt
{
public Member Member { get; set; }
public Claim OriginalClaim { get; set; }
public Claim AltClaim { get; set; }
public double Savings { get; set; }
}
对于每个成员和原始声明,可以有一个或多个 AltClaim。所以我要做的是为每个成员/原始索赔获取每个 AltClaim。我将将数据映射到的新对象如下所示:
public class Alternative
{
public Member Member { get; set; }
public Claim OriginalClaim { get; set; }
public List<AlternativeClaim> AlternativeClaims { get; set; }
}
public class AlternativeClaim
{
public Claim AltClaim { get; set; }
public double Savings { get; set; }
}
我已经能够通过 LINQ 对内容进行分组,但它正在生成一个替代列表,其中成员和原始声明的重复次数与替代声明一样多。这是我到目前为止的代码:
public void Test(List<List<Alt>> alternatives)
{
var test = from alts in alternatives
from alt in alts
group alts by new { alt.Member, alt.OriginalClaim } into a
select a;
foreach (var a in test)
{
Console.WriteLine("Auth {0}", a.Key.OriginalClaim.Id);
Console.WriteLine("MemberId {0}", a.Key.Member.Id);
foreach (var alt in a.SelectMany(x => x))
{
[write out alt.AltClaim properties in console here]
}
}
}
我相信我的问题出在 LINQ 查询上。我对 LINQ 不是很熟悉,所以有没有人可以帮助我形成这个(或至少为我指出正确的方向),这样我就不会得到重复项?谢谢!!
编辑(解决方案):
对我有用的解决方案是以下两个答案的组合。接受的答案是我使用的 LINQ 查询,但如果没有 Thomas F 的答案,我无法正确分组。在我分组的类上实现 IEquatable<> 是关键。
非常感谢大家!在这个问题上,你在你的帮助下教会了我很多。
var alts = alternatives.SelectMany(x => x);
var res = alts.GroupBy(alt => Tuple.Create(alt.Member, alt.OriginalClaim))
.Select(g => new Alternative
{
Member = g.Key.Item1,
OriginalClaim = g.Key.Item2,
AlternativeClaims = g.Select(x => new AlternativeClaim {AltClaim = x.AltClaim, Savings = x.Savings}).ToList()
});
foreach (var a in res)
{
Console.WriteLine("Auth {0}", a.OriginalClaim.Id);
Console.WriteLine("MemberId {0}", a.Member.Id);
foreach (var alt in a.AlternativeClaims.OrderByDescending(c => c.Savings))
{
Console.WriteLine("'tSavings = {0};Id = {1};",alt.Savings, alt.AltClaim.Id);
}
}
给出输出:
Auth 51
MemberId 50
Savings = 696969;Id = 513;
Savings = 6969;Id = 512;
Savings = 69;Id = 511;
Auth 52
MemberId 50
Savings = 1002;Id = 522;
Savings = 100;Id = 521;
Auth 102
MemberId 100
Savings = 1022;Id = 1022;
Savings = 1021;Id = 1021;
测试代码
[Test]
public void Test()
{
var member1 = new Member {Id = 50};
var member1Claim1 = new Claim {Id = 51};
var member1Claim2 = new Claim {Id = 52};
var member2 = new Member { Id = 100 };
var member2Claim1 = new Claim { Id = 101 };
var member2Claim2 = new Claim { Id = 102 };
var alternatives = new List<List<Alt>>()
{
new List<Alt>
{
new Alt
{
Member = member1,
OriginalClaim = member1Claim1,
AltClaim = new Claim {Id = 511},
Savings = 69
},
new Alt
{
Member = member1,
OriginalClaim = member1Claim1,
AltClaim = new Claim {Id = 512},
Savings = 6969
},
new Alt
{
Member = member1,
OriginalClaim = member1Claim1,
AltClaim = new Claim {Id = 513},
Savings = 696969
},
new Alt
{
Member = member1,
OriginalClaim = member1Claim2,
AltClaim = new Claim {Id = 521},
Savings = 100
},
new Alt
{
Member = member1,
OriginalClaim = member1Claim2,
AltClaim = new Claim {Id = 522},
Savings = 1002
}
},
new List<Alt>
{
new Alt
{
Member = member2,
OriginalClaim = member2Claim2,
AltClaim = new Claim {Id = 1021},
Savings = 1021
},
new Alt
{
Member = member2,
OriginalClaim = member2Claim2,
AltClaim = new Claim {Id = 1022},
Savings = 1022
}
}
};
}
为了完整起见:
public class Alt
{
public Member Member { get; set; }
public Claim OriginalClaim { get; set; }
public Claim AltClaim { get; set; }
public double Savings { get; set; }
}
public class Claim
{
public int Id { get; set; }
}
public class Member
{
public int Id { get; set; }
}
public class Alternative
{
public Member Member { get; set; }
public Claim OriginalClaim { get; set; }
public List<AlternativeClaim> AlternativeClaims { get; set; }
}
public class AlternativeClaim
{
public Claim AltClaim { get; set; }
public double Savings { get; set; }
}
您的成员类和声明类是否实现了 IEquatable?
如果没有,我怀疑分组不起作用,因为正在通过引用比较成员和声明实例。由于您提到您以 JSON 形式从服务接收数据,因此您的所有 Alt 很可能具有不同的成员和声明实例。因此,即使它们的属性具有相同的值,它们也永远不会属于同一组。
要使分组正常工作,您可以执行以下操作之一:
-
如果可用,请从"成员和声明"中选择一个唯一条件(如 ID 或名称),并按该条件进行分组:
var test = from alts in alternatives from alt in alts group alts by new { MemberId = alt.Member.Id, OriginalClaimId = alt.OriginalClaim.Id } into a select a; foreach (var a in test) { Console.WriteLine("Auth {0}", a.Key.OriginalClaimId); Console.WriteLine("MemberId {0}", a.Key.MemberId); foreach (var alt in a.SelectMany(x => x)) [write out alt.AltClaim properties in console here] }
-
为您的会员和索赔实施 IEquatable 和 IEquatable。
public class Member : IEquatable<Member> { public bool Equals(Member other) { return Id == other.Id; } public override bool Equals(object obj) { var other = obj as Member; if (other == null) return false; return Equals(other); } public override int GetHashCode() { // Whenever IEquatable is implemented, GetHashCode() must also be overridden. return Id.GetHashCode(); } // Rest of the class... }
尝试alternatives.SelectMany(alt => new { alt.Member, alt.OriginalClaim })