如何从列表框中获取标签内容
本文关键字:获取 标签 列表 | 更新日期: 2023-09-27 18:09:13
我在列表框中有一个标签,列表框中有许多数据模板,每个模板都有一个标签,我无法从。cs文件后面的代码中检索标签的内容,数据模板是常见的,但每个标签在里面都有不同的文本。,那么如何从模板中检索每个标签值呢?模板也有一个删除按钮,用于删除所选模板。因此,如果用户删除了模板,那么listbox内的模板就会减少,那么我现在如何遍历标签来检索值呢?
下面是模板 的代码<TabItem>
<Canvas Height="700" Width="850">
<Canvas.Resources>
<XmlDataProvider x:Key="Tasks" XPath="tasks"
Source="http://store.tymesheet.com/templates/Software-Developer.xml"/>
<DataTemplate x:Key="tasktemplate1">
<Canvas Height="50" Width="850">
<Label x:Name="tasklabel" Content="{Binding XPath=name}" Height="30"
Width="170" Canvas.Top="10" Canvas.Left="150"
Background="LightGray"/>
<TextBox Height="30" Width="100" Canvas.Top="10"
Canvas.Left="370" Background="AliceBlue"/>
<Label Canvas.Left="500" Canvas.Top="10">$</Label>
<Button Click="deletebuttonclick"
Canvas.Top="12" Height="10" Width="30"
Canvas.Left="600"/>
</Canvas>
</DataTemplate>
</Canvas.Resources>
<ListBox ItemTemplate="{StaticResource tasktemplate1}"
ItemsSource="{Binding Tasks}"
x:Name="tasklistBox" Height="700" Width="850"/>
<Label Canvas.Top="-18" Canvas.Left="185">Select Task</Label>
<Label Canvas.Top="-18" Canvas.Left="377" RenderTransformOrigin="0.58,0.462">Enter Bill Rates</Label>
<Button Click="addtask" Canvas.Left="39" Canvas.Top="575" Width="139">Click to add the task</Button>
</Canvas>
</TabItem>
下面是按钮
的后台代码 private void addtask(object sender,RoutedEventArgs e)
{
foreach (ListBoxItem item in tasklistBox.Items)
{
// Getting the ContentPresenter of myListBoxItem
ContentPresenter myContentPresenter = FindVisualChild<ContentPresenter>(item);
// Finding textBlock from the DataTemplate that is set on that ContentPresenter
DataTemplate myDataTemplate = myContentPresenter.ContentTemplate;
System.Windows.Forms.Label mydata = (System.Windows.Forms.Label)myDataTemplate.FindName("tasklabel", myContentPresenter);
// Do something to the DataTemplate-generated TextBlock
System.Windows.MessageBox.Show("element" + mydata);
}
}
在我的。cs文件中,我也加载了用于删除模板的xml文件。
{
InitializeComponent();
XmlDocument doc = new XmlDocument();
doc.Load("http://store.tymesheet.com/templates/Software-Developer.xml");
var taskList = doc.ChildNodes.OfType<XmlNode>()
.Where(node => node.Name == "tasks")
.SelectMany(node => node.ChildNodes.OfType<XmlNode>());
Tasks = new ObservableCollection<XmlNode>(taskList);
this.DataContext = this;
}
任何帮助,多谢。
将foreach循环替换为:
foreach (object item in taskslistBox.Items)
{
var listBoxItem = taskslistBox.ItemContainerGenerator.ContainerFromItem(item);
var myContentPresenter = FindVisualChild<ContentPresenter>(listBoxItem);
var myDataTemplate = myContentPresenter.ContentTemplate;
var mydata = (Label)myDataTemplate.FindName("tasklabel", myContentPresenter);
var xmlElement = (XmlElement)mydata.Content;
MessageBox.Show("element " + xmlElement.InnerText);
}