将弹出控件放置在ListView的单元格上

本文关键字：ListView 单元格 控件 | 更新日期: 2023-09-27 18:09:36

我有一个列表视图，并希望在按下按钮时显示弹出窗口上的更多信息。无论如何，我的listview看起来像:

<ListView Name="TableListView">
  <ListView.View>
    <GridView>
      <GridViewColumn  Width="50"
                       Header="ID">
        <GridViewColumn.CellTemplate>
          <DataTemplate>
            <Label Content="{Binding Id}"
                   HorizontalAlignment="Center" />
          </DataTemplate>
        </GridViewColumn.CellTemplate>
      </GridViewColumn>
      <!-- I am having trouble with this column! -->
      <GridViewColumn  Width="50"
                       Header="ID">
        <GridViewColumn.CellTemplate>
          <DataTemplate>
            <StackPanel>
              <Button Content="Click to show more Info">
                <Button.Triggers>
                  <Trigger Property="IsMouseOver"
                           Value="True">
                    <Setter TargetName="PopupSelectFile"
                            Property="IsOpen"
                            Value="True">
                    </Setter>
                  </Trigger>
                </Button.Triggers>
              </Button>
              <Popup x:Name="PopupSelectFile">
                <Button Width="100"
                        Height="100"></Button>
              </Popup>
            </StackPanel>
          </DataTemplate>
        </GridViewColumn.CellTemplate>
      </GridViewColumn>
    </GridView>
  </ListView.View>
</ListView>

基本上我想显示一个弹出(PopupSelectFile)当第二列上的按钮被点击。

将弹出控件放置在ListView的单元格上

<ToggleButton x:Name="theButton">
    ...
</ToggleButton>
<Popup IsOpen="{Binding IsChecked, ElementName=theButton">
    ...
</Popup>
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