如何对Web Api动作进行post调用

本文关键字：post 调用 Web Api | 更新日期: 2023-09-27 18:09:47

我创建了一个Web API Action 

[HttpPost]
public void Load(string siteName, string providerName, UserDetails userDetails)
{
// implementation
}

我为此注册的路由如下(不确定是否正确?):

 config.Routes.MapHttpRoute(
             name: "loadUserDetails",
             routeTemplate: "sites/{siteName}/User/Load/{providerName}/{userDetailsList}",
             defaults: new
             {
                 controller = "User",
                 action = "Load",
                 providerName = UrlParameter.Optional
             });

providerName参数应该是可选的，我正在使用Xml序列化。

动作应该响应下面的url示例:

http://www.domain.com/sites/site1/user/load/provider1/[some user details in the post]
or
http://www.domain.com/sites/site1/user/load/[some user details in the post]

我如何对这个动作进行post调用，以便测试我的服务?

如何对Web Api动作进行post调用

From: HTTP request with post

HttpWebRequest request =
    (HttpWebRequest)WebRequest.Create(@"http:''domain.com'page.asp");
ASCIIEncoding encoding = new ASCIIEncoding();
string postData = "username=user";
postData += "&password=pass";
byte[] data = encoding.GetBytes(postData);
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = data.Length;
using (Stream stream = request.GetRequestStream())
{
    stream.Write(data,0,data.Length);
}
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
string responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

如果你的问题是如何测试你的动作，你可以使用Fidler。

见http://www.mehdi-khalili.com/fiddler-in-action/part-2

查看此处使用RestSharp和Web Request的响应:

http://pooyakhamooshi.blogspot.co.uk/2013/04/how-to-post-request-to-web-api-web.html

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