重复消除分配

我目前正在网上注册一个c#编程入门课程。很难联系我的老师寻求帮助，我正在努力解决这个问题，我非常接近，但我的解决方案必须与老师的解决方案100%匹配。我必须在列表当前的努力没有成功之前移动错误消息。请帮助我知道这可能是一个愚蠢的错误，但我仍然是一个初学者。我的代码到目前为止:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace midterm
{
class Program
{
    static void Main(string[] args)
    {
        int size;
        Console.WriteLine("How many numbers will you enter?");
        size = Convert.ToInt32(Console.ReadLine());
        int[] numbers = new int[size];
        int count = 0;
        while (count < size)
        {
            Console.Write("Enter number: ");
            int number = Convert.ToInt32(Console.ReadLine());
            if (number >= 10 && number <= 100)
            {
                bool containsNumber = false;

                for (int j = 0; j < count; j++)
                {
                    if (number == numbers[j])
                        containsNumber = true;

                    if (numbers[j] > 0)
                        Console.WriteLine("{0}", numbers[j]);
                }
                if (!containsNumber)
                {
                    if (count < numbers.Length)
                        numbers[count] = number;
                    Console.WriteLine(number);
                }
                 else
                {
                   Console.WriteLine("{0} has already been entered", number);
               }
                ++count;
            }
            else
                Console.WriteLine("number must be between 10 and 100");
        }
        Console.ReadLine();
    }
}
}

测试用例:

10
90
50
90
22
18
65
22
92
100
20

正确的解决方案:

How many numbers will you enter? 
Enter number: 90 
Enter number: 90 
50 
Enter number: 90 has already been entered
90
50
Enter number: 90
50
22
Enter number: 90
50
22
18
Enter number: 90
50
22
18
65
Enter number: 22 has already been entered
90
50
22
18
65
Enter number: 90
50
22
18
65
92
Enter number: 90
50
22
18
65
92
100
Enter number: 90
50
22
18
65
92
100
20

我的解决方案:

How many numbers will you enter?
Enter number: 90
Enter number: 90
50
Enter number: 90
50
90 has already been entered
Enter number: 90
50
22
Enter number: 90
50
22
18
Enter number: 90
50
22
18
65
Enter number: 90
50
22
18
65
22 has already been entered
Enter number: 90
50
22
18
65
92
Enter number: 90
50
22
18
65
92
100
Enter number: 90
50
22
18
65
92
100
20

if (number >= 10 && number <= 100)
{
   bool containsNumber = false;
   for (int j = 0; j < count; j++)
   {
       if (number == numbers[j])
            containsNumber = true;
   }
   if (!containsNumber)
   {
      if (count < numbers.Length)
            numbers[count] = number;
      Console.WriteLine(number);
   }
   else
   {
       Console.WriteLine("{0} has already been entered", number);
   }
   for (int j = 0; j < count; j++)
   {
       if (numbers[j] > 0)
          Console.WriteLine("{0}", numbers[j]);
   }
   ++count;