将byte[]保存为Zip，转换为流，作为邮件附件发送邮件-附件文档的正确方式

本文关键字：文档 方式 byte 保存 Zip 转换 | 更新日期: 2023-09-27 18:10:03

下面是我使用的代码。基本上，它只是循环遍历一个数组，将文件添加到压缩文件中，然后将压缩文件保存到内存流中，然后通过电子邮件发送附件。

当我在调试中查看项目时，我可以看到zipfile有大约20兆字节的数据。当我收到附件时，它只有大约230位的数据，没有内容。任何想法吗?

byteCount = byteCount + docs[holder].FileSize;
            if (byteCount > byteLimit)
            {
                //create a new stream and save the stream to the zip file
                System.IO.MemoryStream attachmentstream = new System.IO.MemoryStream();
                zip.Save(attachmentstream);
                //create the attachment and send that attachment to the mail
                Attachment data = new Attachment(attachmentstream, "documentrequest.zip");
                theMailMessage.Attachments.Add(data);
                //send Mail
                SmtpClient theClient = new SmtpClient("mymail");
                theClient.UseDefaultCredentials = false;
                System.Net.NetworkCredential theCredential = new System.Net.NetworkCredential("bytebte", "2323232");
                theClient.Credentials = theCredential;
                theClient.Send(theMailMessage);
                zip = new ZipFile();
                //iterate Document Holder
                holder++;
            }
            else
            {
                //create the stream and add it to the zip file
                //System.IO.MemoryStream stream = new System.IO.MemoryStream(docs[holder].FileData);
                zip.AddEntry("DocId_"+docs[holder].DocumentId+"_"+docs[holder].FileName, docs[holder].FileData);
                holder++;
            }

问题在这里，Attachment data = new Attachment(attachmentstream, "documentrequest.zip");，一旦我看附件，它的大小是-1，那么什么是正确的方式来附加这个项目?

将byte[]保存为Zip，转换为流，作为邮件附件发送邮件-附件文档的正确方式

我怀疑对zip.Save的调用在写完流之后关闭了流。您可能最终不得不将字节复制到数组中，然后创建一个新的MemoryStream用于读取。例如:

//create a new stream and save the stream to the zip file
byte[] streamBytes;
using (var ms = new MemoryStream())
{
    zip.Save(ms);
    // copy the bytes
    streamBytes = ms.ToArray();
}
// create a stream for the attachment
using (var attachmentStream = new MemoryStream(streamBytes))
{
    //create the attachment and send that attachment to the mail
    Attachment data = new Attachment(attachmentstream, "documentrequest.zip");
    theMailMessage.Attachments.Add(data);
    // rest of your code here
}
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