格式化ISO datetime为March 12, 2014 12:00:00
本文关键字:2014 March ISO datetime 格式化 | 更新日期: 2023-09-27 17:50:58
如何将ISO日期(20140312120000或2014-03-12 12:00:00)转换为"March 12, 2014 12:00:00" .
谢谢。
DateTime thisDate1 = new DateTime(2014, 3, 12);
Console.WriteLine("Today is " + thisDate1.ToString("MMMM dd, yyyy") + ".");
// The example displays the following output:
// Today is March 12, 2011.
你不能用普通的DateTime来解析它。解析方法,
DateTime.ParseExact(date, "yyyyMMdd''HHmmss", CultureInfo.InvariantCulture)
我是这样解决的:DateTime.Parse(isodate)。ToString("MMMM dd, yyyy HH:mm:ss").
您要做的是将输入字符串解析为DateTime
,然后将其转换为您想要的形式。ParseExact
和ToString
方法可以完成这项工作。
public string MyFromat(string s)
{
var inputForms = new string[]
{
"yyyyMMdd''HHmmss",
"yyyy-MM-dd' 'HH':'mm':'ss"
};
var time = DateTime.ParseExact(s, inputForms, , CultureInfo.InvariantCulture);
return time.ToString(""MMMM dd, yyyy HH':'mm':'dd", , CultureInfo.InvariantCulture);
}
您的两个示例形式不是ISO
。如果要解析ISO日期时间,则使用DateTimeOffset
表示时间,并使用以下输入格式:
static readonly string[] Iso8061DateTimeForms = new string[]
{
"yyyyMMdd'T'HHmmss",
"yyyyMMdd'T'HHmmss'Z'",
"yyyyMMdd'T'HHmmsszzz",
"yyyyMMdd'T'HHmmss'.'fffffff",
"yyyyMMdd'T'HHmmss'.'fffffff'Z'",
"yyyyMMdd'T'HHmmss'.'fffffffzzz",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'",
"yyyy'-'MM'-'dd'T'HH':'mm':'sszzz",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffffff",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffffff'Z'",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffffffzzz",
};
解析ISO 8061时间的完整实现是:
public static DateTimeOffset ParseIso8061Time(string s)
{
var styles = DateTimeStyles.AllowWhiteSpaces |
(s.EndsWith("Z")
? DateTimeStyles.AssumeUniversal
: DateTimeStyles.AssumeLocal);
return DateTimeOffset.ParseExact(s, Iso8061DateTimeForms,
CultureInfo.InvariantCulture, styles);
}