在c#中使用xsl转换xml显示空文件
本文关键字:xml 显示 文件 转换 xsl | 更新日期: 2023-09-27 17:51:02
我正在尝试使用xsl文件转换xml文件,并在新窗口中打开转换后的xml文件。我从sql server数据库中获取xml和xsl文件作为字符串,将它们转换为xml文档,然后使用xsl转换xml文件,下面是我的代码
IQueryable<DataDictionaryReport> reportsQuery = from d in dataDictionaryContext.DataDictionaryReports
where d.DBID == j
select d;
string displayXML=null ;
string displayXSL=null;
foreach (var report in reportsQuery)
{
displayXML = report.ReportXML;
displayXSL = report.ReportXSL;
}
//myLabel.Text = displayXML;
XmlDocument docXML = new XmlDocument();
docXML.LoadXml(displayXML);
XmlTextWriter writerXML = new XmlTextWriter(Server.MapPath("/document/Model Report.xml"), null);
writerXML.Formatting = Formatting.Indented;
docXML.Save(writerXML);
XmlDocument docXSL= new XmlDocument();
docXSL.LoadXml(displayXSL);
XmlTextWriter writerXSL = new XmlTextWriter(Server.MapPath("/document/Model Report.xsl"), null);
writerXSL.Formatting = Formatting.Indented;
docXSL.Save(writerXSL);
try
{
XmlTextWriter writer = new XmlTextWriter(Server.MapPath("/document/output.xml"), null);
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load("/document/Model Report.xsl");
xslt.Transform("/document/Model Report.xml", "/document/output.xml");
}
catch (Exception ex)
{
Console.WriteLine(ex.ToString());
}
string newWin = "window.open('" + "/document/output.xml" + "');";
ClientScript.RegisterStartupScript(this.GetType(), "pop", newWin, true);
我的output.xml显示一个空文件。我发布了xsl文件的前几行代码,可能太长了,
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:key name="IDs" match="*" use="@id" />
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Table/Columns Report</title>
<script type="text/javascript">
// <![CDATA[
function toggle(element, togimg) {
if (element.style.display == 'none') {
element.style.display = 'block';
togimg.src="images/collapse.gif";
}
else {
element.style.display = 'none';
togimg.src="images/expand.gif";
}
}
// ]]></script>
</head>
...
非常感谢任何帮助。
显示一个空文件,通过将XML文档流式传输到内存,然后从内存中读取来解决这个错误。代码如下,
MemoryStream stm = new MemoryStream();
xslt.Transform(docXML, null, stm);
stm.Position = 1;
StreamReader sr = new StreamReader(stm);
Response.Write(sr.ReadToEnd());