将CSV解析为模型

本文关键字：模型 CSV | 更新日期: 2023-09-27 18:11:29

我试图解析CSV到模型，但是，我的IEnumerable总是空的。这个代码有什么问题吗?

private IEnumerable<CandidatesDTO> FileToDto(byte[] file)
{
    System.Text.UTF8Encoding enc = new System.Text.UTF8Encoding();
    IEnumerable<CandidatesDTO> query = null;
    string[] separators = { ",", ".", "!", "?", ";", ":", " " };
    try
    {
        var str = enc.GetString(file);
        query = from line in str
                let data = str.Split(separators, StringSplitOptions.RemoveEmptyEntries)
                select new CandidatesDTO
                {
                    Id = Int32.Parse(data[0]),
                    Name = data[1],
                    DOB = DateTime.Parse(data[2], CultureInfo.InvariantCulture),
                    Phone = data[3],
                    Email = data[4]
                };
    }
    catch (Exception ex)
    {
        throw new Exception(ex.Message);
    }
    return query;
}

。我发现有例外-"输入字符串格式不正确"。似乎有些不正确的类型传递给string，这导致了FormatException.

将CSV解析为模型

从查看代码，我认为linq将str视为IEnumerable<char>。您可能需要执行str.Split("'r'n")或任何行分隔符，以便您可以获得每一行。

private IEnumerable<CandidatesDTO> FileToDto(byte[] file)
{
    System.Text.UTF8Encoding enc = new System.Text.UTF8Encoding();
    IEnumerable<CandidatesDTO> query = null;
    string[] separators = { ",", ".", "!", "?", ";", ":", " " };
    try
    {
        var str = enc.GetString(file);
        query = from line in str.Split(new [] {"'n'r"}, StringSplitOptions.RemoveEmptyEntries)
                let data = line.Split(separators, StringSplitOptions.RemoveEmptyEntries)
                select new CandidatesDTO
                {
                    Id = Int32.Parse(data[0]),
                    Name = data[1],
                    DOB = DateTime.Parse(data[2], CultureInfo.InvariantCulture),
                    Phone = data[3],
                    Email = data[4]
                };
    }
    catch (Exception ex)
    {
        throw new Exception(ex.Message);
    }
    return query;
}
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