REQ/REP模式下的ZeroMQ FiniteStateMachineException
本文关键字:ZeroMQ FiniteStateMachineException 模式 REP REQ | 更新日期: 2023-09-27 18:11:35
我有两个简单的组件,它们应该使用REQ/REP ZeroMQ模式相互通信。服务器(REP套接字)在Python中使用pyzmq:
实现。import zmq
def launch_server():
print "Launching server"
with zmq.Context.instance() as ctx:
socket = ctx.socket(zmq.REP)
socket.bind('tcp://127.0.0.1:5555')
while True:
msg = socket.recv()
print "EOM'n'n"
使用NetMQ库用c#编写的客户端(REQ套接字):
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using NetMQ;
namespace PyNetMQTest
{
class Program
{
static void Main(string[] args)
{
string msg;
NetMQ.Sockets.RequestSocket socket = new NetMQ.Sockets.RequestSocket();
socket.Connect("tcp://127.0.0.1:5555");
for(int i=0; i<5; i++)
socket.SendFrame("test_"+i);
}
}
}
Python Server的实现已经经过测试,通过与使用Python实现的REQ套接字通信可以正常工作。但是c# REQ套接字在循环的第一次迭代中抛出以下错误,并且没有消息到达服务器:
类型为'NetMQ '的未处理异常。NetMQ.dll中发生了FiniteStateMachineException附加信息:无法发送另一个请求
异常堆栈:
at NetMQ.Core.Patterns.Req.XSend(Msg& msg)
at NetMQ.Core.SocketBase.TrySend(Msg& msg, TimeSpan timeout, Boolean more)
at NetMQ.NetMQSocket.TrySend(Msg& msg, TimeSpan timeout, Boolean more)
at NetMQ.OutgoingSocketExtensions.Send(IOutgoingSocket socket, Msg& msg, Boolean more)
at NetMQ.OutgoingSocketExtensions.SendFrame(IOutgoingSocket socket, String message, Boolean more)
at PyNetMQTest.Program.Main(String[] args) in d:'users'emes'documents'visual studio 2015'Projects'PyNetMQ Test'PyNetMQTest'Program.cs:line 20
at System.AppDomain._nExecuteAssembly(RuntimeAssembly assembly, String[] args)
at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
at System.Threading.ExecutionContext.RunInternal(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean preserveSyncCtx)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean preserveSyncCtx)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
at System.Threading.ThreadHelper.ThreadStart()
这些是我使用ZMQ的第一步,c#代码取自库文档。是什么使代码抛出这个错误?
我正在使用:
- pyzmq 14.7
- NetMQ 3.3.3.4
- 。NET 4.6
====================== 解决方案 ======================
正如@somdoron在他的回答中解释的那样,根本原因是两个套接字在能够被重用之前都需要完成发送/接收的完整周期。事实上,在python中实现的REP套接字也从未改变过它的状态,所以错误存在于python和c#代码中。下面是固定的代码:
代表插座
import zmq
def launch_server():
print "Launching server"
with zmq.Context.instance() as ctx:
socket = ctx.socket(zmq.REP)
socket.bind('tcp://127.0.0.1:5555')
while True:
msg = socket.recv()
socket.send("reply to "+msg)
print "EOM'n'n"
要求的套接字
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using NetMQ;
namespace PyNetMQTest
{
class Program
{
static void Main(string[] args)
{
NetMQ.Sockets.RequestSocket socket = new NetMQ.Sockets.RequestSocket();
socket.Connect("tcp://127.0.0.1:5555");
string msg, reply;
while (true)
{
Console.WriteLine("Type message: ");
msg = Console.ReadLine();
Console.WriteLine("Sending : " + msg);
socket.SendFrame(msg);
reply = socket.ReceiveFrameString();
Console.WriteLine("Received: " + reply + Environment.NewLine);
}
}
}
}
请求和响应套接字都是状态机,有了请求你必须先发送然后调用接收,你不能连续调用5个发送。
与Response相反,你必须先调用Receive。
如果一方只发送,另一方只接收,你可以使用Push-Pull模式而不是Req-Rep。如果需要双向通信,也可以使用Dealer-Router。无论如何,Req-Rep的用法似乎是不正确的。