从具有相同搜索条件的数组中打印多行

本文关键字：数组 打印 条件 搜索 | 更新日期: 2023-09-27 18:11:42

我正在做一个应用程序，我给出航班的ID，程序打印该航班上所有乘客的信息。我设法这样做，这样我就可以用他的身份证搜索乘客，并打印他所乘坐的航班信息，但我不能用其他方式来做。任何建议吗?这些是数组:

    Passenger[] passengers = new Passenger[] {
            new Passenger("John", 100, 200),
            new Passenger("Mark", 101, 200),
            new Passenger("Charlie", 102, 201)};
    Flight[] flights = new Flight[] {
            new Flight(200, "Berlin", "Moscow", "05.10.2016"),
            new Flight(201, "Paris", "Madrid", "06.10.2016")};

Passenger和Flight具有相同的ID，因此我使用它来链接数组。

从具有相同搜索条件的数组中打印多行

user2023861打败了我，但这里有一个更完整的示例，使用where子句过滤航班ID的结果完整的代码在这里:https://github.com/drGarbinsky/PrintFlightsExample

   var data = from f in flights
                   join p in passengers on f.ID equals p.Flight
                   where f.ID == searchId
                   select new { flight = f, passenger = p };
        if (data.Any())
        {
            var format = "{0} departs {1} for {2} on flight {3} in seat {4} on {5}";
            foreach (var item in data)
            {
                Console.WriteLine(string.Format(format, item.passenger.Name, item.flight.Origin, item.flight.Destination,item.flight.ID, item.passenger.Seat, item.flight.Date));
            }
        }

输出如下:

John departs Berlin for Moscow on flight 200 in seat 100 on 05.10.2016
Mark departs Berlin for Moscow on flight 200 in seat 101 on 05.10.2016

您可以像这样通过航班id将数组连接在一起:

var joined = from p in passengers
             join f in flights on p.FlightId equals f.FlightId
             select new { p, f };

然后你可以像这样循环:

foreach(var match in joined) {
    Console.WriteLine("Passenger name = " + match.p.Name);
    Console.WriteLine("Flight time = " + match.f.FlightTime);
}
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