计算两个日期之间的差异并将其存储在数组中

本文关键字：存储 数组 两个 之间 日期 计算 | 更新日期: 2023-09-27 17:51:06

我想计算两个日期之间的差异，一个选择表单dateTimePicker1和另一个2014年2月20日，并将其存储在字符串中添加到我的数组"Patient"中，并能够在另一个表单标签中显示它。

到目前为止我没有错误，但程序不显示日期之间的差异。这是我到目前为止的代码:

TimeSpan getDateDifference(DateTime date1, DateTime date2)
{
    TimeSpan ts = date1 - date2;
    int differenceInDays = ts.Days;
    string differenceAsString = differenceInDays.ToString();
    return ts;
}
public class Patient
{
    public string patientidString;
    public string firstNameString;
    public string lastNameString;
    public string dateString;
    public string differenceAsString;
    public Patient()
    {
        patientidString = "";
        firstNameString = "";
        lastNameString = "";
        dateString = "";
    }
}
//Array
Patient[] patientInfo = new Patient[10];
private void button1_Click(object sender, EventArgs e)
{
    TimeSpan difference = getDateDifference(new DateTime(2014, 2, 20), dateTimePicker1.Value);
    if (textBox1.Text.Length == 0 || textBox2.Text.Length == 0 || textBox3.Text.Length == 0)
    {
        MessageBox.Show(" Patient id, first name and last name cannot be empty");
    }
    else
       try
       {
           foreach (Patient patientinfoIndex in patientInfo)
               patientInfo[itemCountInteger].patientidString = textBox1.Text;
           patientInfo[itemCountInteger].firstNameString = textBox2.Text;
           patientInfo[itemCountInteger].lastNameString = textBox3.Text;
           patientInfo[itemCountInteger].dateString = dateTimePicker1.Text;
           string names = patientInfo[itemCountInteger].patientidString + "  " + patientInfo[itemCountInteger].firstNameString + " " + patientInfo[itemCountInteger].lastNameString;
        listBox1.Items.Add(names);
        itemCountInteger++;
        listBox1.SelectedItem = names;
    }
    catch
    {
        MessageBox.Show("Contacts are limited to 20. Please delete some contacts prior to adding more.");
    }
}
//Search Button search a patients name and display his surname in the label if patient is found  display his surname
private void button2_Click(object sender, EventArgs e)
{
    int intTest = 0;
    for (int x = 0; x < patientInfo.Length; x++)
    {
        if (textBox4.Text == patientInfo[x].patientidString)
        {
            label6.Text = (patientInfo[x].firstNameString + "  " + patientInfo[x].lastNameString);
            PatientForm patientform = new PatientForm();
            patientform.Show();
            patientform.label6.Text = (patientInfo[x].patientidString);
            patientform.label7.Text = (patientInfo[x].firstNameString);
            patientform.label8.Text =(patientInfo[x].lastNameString);
            patientform.dateTimePicker1.Text = (patientInfo[x].dateString);
            patientform.label9.Text = (patientInfo[x].differenceAsString);
            intTest = 1;
            break;
        }
    }
    if (intTest == 0)
    {
        label6.Text = ("not found");
    }
}

计算两个日期之间的差异并将其存储在数组中

你没有给

添加任何值
patientInfo[itemCountInteger].differenceAsString;

这就是为什么没有显示，它是一个空的string。

试着给它一个值:

patientInfo[itemCountInteger].differenceAsString = difference.Days.ToString();

应该是这样的:

private void button1_Click(object sender, EventArgs e)
{
    TimeSpan difference = getDateDifference(new DateTime(2014, 2, 20), dateTimePicker1.Value);
    if (textBox1.Text.Length == 0 || textBox2.Text.Length == 0 || textBox3.Text.Length == 0)
    {
        MessageBox.Show(" Patient id, first name and last name cannot be empty");
    }
    else
       try
       {
           foreach (Patient patientinfoIndex in patientInfo)
           {
               patientInfo[itemCountInteger].patientidString = textBox1.Text;
               patientInfo[itemCountInteger].firstNameString = textBox2.Text;
               patientInfo[itemCountInteger].lastNameString = textBox3.Text;
               patientInfo[itemCountInteger].dateString = dateTimePicker1.Text;
               patientInfo[itemCountInteger].differenceAsString= difference.Days.ToString();
               string names = patientInfo[itemCountInteger].patientidString + "  " +   patientInfo[itemCountInteger].firstNameString + " " + patientInfo[itemCountInteger].lastNameString;
               listBox1.Items.Add(names);
               itemCountInteger++;
               listBox1.SelectedItem = names;
        } 
    }
    catch
    {
        MessageBox.Show("Contacts are limited to 20. Please delete some contacts prior to adding more.");
    }
}

试着显示这个:

DateTime a=...
DateTime b=...
label.Text=(a - b).TotalDays.ToString();

在计算日期之间的差异时，人们几乎总是认为它们是完整的日期。这意味着您必须将该范围视为完全包含。

以2014-01-01到2014-01-02为例。一共有多少天?你问的几乎所有人都会说two。但是，DateTime始终是日期和时间。您可能指定了午夜的时间，或者您可能只是忽略了时间部分。但它还在那里。

一旦你有了一个时间组件，那么大多数人自然会使结束部分排他的。

2014-01-01 00:00:00到2014-01-02 00:00:00范围内有多少小时? 24 。

因此，如果您的用户界面只要求日期，并且您使用DateTime来存储它们，那么不要忘记在差异中添加一天，以说明结束日期将被视为一天的结束，而不是开始。

DateTime startDate = new DateTime(2014,1,1);
DateTime endDate = new DateTime(2014,1,2);
TimeSpan difference = endDate - startDate + TimeSpan.FromDays(1);
int days = (int) difference.TotalDays;

当然，您可以通过验证解析方法之一从UI中获取日期，例如DateTime.TryParse(如果您的UI是文化感知的)或DateTime.TryParseExact(如果您打算使用不变文化并告诉用户以特定格式输入日期)。

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