c# async / await未观察异常
本文关键字:观察 异常 await async | 更新日期: 2023-09-27 18:12:11
我想理解为什么下面的代码:
async void Handle_Clicked(object sender, System.EventArgs e)
{
try
{
await CrashAsync("aaa");
}
catch (Exception exception)
{
Log($"observed exception");
Log($"Exception: {exception.Message}");
}
}
private async Task CrashAsync(string title)
{
Log($"CrashAsync ({title}) - before");
await Task.Delay(1000);
throw new Exception($"CrashAsync ({title})");
Log($"CrashAsync ({title}) - after");
}
产生预期的结果:
thread #1: CrashAsync (aaa) - before
线程#1:观察到异常
线程#1:Exception: CrashAsync (aaa)
但是如果我把它改成这个
async void Handle_Clicked(object sender, System.EventArgs e)
{
try
{
await CrashAsync("aaa").ContinueWith(async (t) =>
{
await CrashAsync("bbb");
},TaskContinuationOptions.OnlyOnRanToCompletion);
}
catch (Exception exception)
{
Log($"observed exception");
Log($"Exception: {exception.Message}");
}
}
得到以下输出:
thread #1: CrashAsync (aaa) - before
线程#1:观察到异常
线程#1:Exception: A task was cancelled .
线程#2:unobserved exception
线程#2:System。异常:CrashAsync (aaa)在AsyncTest.AsyncTestPage + c__async3。MoveNext () [0x000ad] in/Users/johndoe/Development/Xamarin/AsyncTest/AsyncTest/asynctestpage . example .cs:82
地点:
TaskScheduler.UnobservedTaskException += (sender, e) =>
{
Debug.WriteLine($"thread #{Environment.CurrentManagedThreadId}: unobserved exception");
foreach (var exception in e.Exception.Flatten().InnerExceptions)
{
Debug.WriteLine($"thread #{Environment.CurrentManagedThreadId}: {exception}");
}
};
连续性条件不满足,因此ContinueWith任务被取消,但为什么我有未观察到的异常?
您等待ContinueWith
返回的Task
,因此您观察到与此Task
相关的异常-它被取消(TaskCanceledException
)。但是你没有观察到CrashAsync抛出的原始异常(所以"CrashAsync aaa")异常,因此你观察到的行为。
static async void Test() {
var originalTask = CrashAsync("aaa");
var onSuccess = originalTask.ContinueWith(async (t) =>
{
await CrashAsync("bbb");
}, TaskContinuationOptions.OnlyOnRanToCompletion);
var onFault = originalTask.ContinueWith(t => {
Log("Observed original exception: " + t.Exception.InnerExceptions[0].Message);
}, TaskContinuationOptions.OnlyOnFaulted);
}
所以简而言之-等待你的任务并捕获异常(如果有的话)。您根本不需要使用ContinueWith
,因为如果您使用await -方法的其余部分已经是一个延续