使用naudio获取1秒音频文件的分贝

本文关键字：文件 音频 naudio 获取 1秒 使用 | 更新日期: 2023-09-27 17:51:10

我想使用naudio计算任何。wav文件的1秒分贝。这是我的代码:

WaveFileReader reader = new WaveFileReader(@"C:'Users'Admin'Desktop'result.wav");
int bytesPerMillisecond = reader.WaveFormat.AverageBytesPerSecond / 1000;            
//byte[] buffer = new byte[reader.Length];
//int read = reader.Read(buffer, 0, (int)reader.Length);
TimeSpan time = new TimeSpan(0, 0, 1);
int bytesPerSecond = (int)time.TotalMilliseconds * bytesPerMillisecond;
byte[] oneSecondBuffer = new byte[bytesPerSecond];
int read = reader.Read(oneSecondBuffer, 0, bytesPerSecond);
short sample16Bit = BitConverter.ToInt16(oneSecondBuffer, 1);
double volume = Math.Abs(sample16Bit / 32768.0);
double decibels = 20 * Math.Log10(volume);
这条线

: 

short sample16Bit = BitConverter.ToInt16(oneSecondBuffer, 1);

返回0。我做错了什么?

使用naudio获取1秒音频文件的分贝

我用另一种方法解决了这个任务。这是一段代码，可以帮助其他人:

var silenceDict = new Dictionary<int, bool>();
using (NAudio.Wave.AudioFileReader wave = new NAudio.Wave.AudioFileReader(filePath))
{
    var samplesPerSecond = wave.WaveFormat.SampleRate * wave.WaveFormat.Channels;
    var readBuffer = new float[samplesPerSecond];
    int samplesRead;
    int i = 1;
    do
    {
        samplesRead = wave.Read(readBuffer, 0, samplesPerSecond);
        if (samplesRead == 0) break;
        var max = readBuffer.Take(samplesRead).Max();
        if ((int)(max * 100) != 0)
            silenceDict.Add(i, false);
        else
            silenceDict.Add(i, true);
        i++;
    } while (samplesRead > 0);
}
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