从文件中加载xml

本文关键字：xml 加载 文件 | 更新日期: 2023-09-27 18:13:06

一直在寻找我的问题的答案。我找到了一种将List转换为xml文件的好方法，但我也想让它返回到一个列表。

我当前的xml文件是这样的:

<Commands>
    <Command command="!command1" response="response1" author="niccon500" count="1237"/>
    <Command command="!command2" response="response2" author="niccon500" count="1337"/>
    <Command command="!command3" response="response3" author="niccon500" count="1437"/>
</Commands>
生成:

var xml = new XElement("Commands", commands.Select(x =>
                      new XElement("Command",
                      new XAttribute("command", x.command),
                      new XAttribute("response", x.response),
                      new XAttribute("author", x.author),
                      new XAttribute("count", x.count))));
            File.WriteAllText(file_path, xml.ToString());

那么，如何从xml文件中获取信息呢?

从文件中加载xml

您可以使用以下代码:

XDocument doc = XDocument.Load(@"myfile.xml");

将XML文件加载到XDocument对象中。

然后您可以使用.Descendants("Commands").Elements()访问<Commands>元素中包含的所有元素并将它们添加到列表中:

 List<Command> lstCommands = new List<Command>();
 foreach(XElement elm in doc.Descendants("Commands").Elements())
 {               
     lstCommands.Add(new Command
                     {
                        command = elm.Attribute("command").Value,
                        response = elm.Attribute("response").Value,
                        author = elm.Attribute("author").Value,
                        count = int.Parse(elm.Attribute("count").Value)
                     });
 }

当使用xml进行持久存储时，首先定义POC类，并用适当的属性修饰它们——如

[XmlType("Command")]
public class CommandXml
{
    [XmlAttribute("command")]
    public string Command { get; set; }
    [XmlAttribute("response")]
    public string Response { get; set; }
    [XmlAttribute("author")]
    public string Author { get; set; }
    [XmlAttribute("count")]
    public int Count { get; set; }
}
[XmlRoot("Commands")]
public class CommandListXml : List<CommandXml>
{
}

反序列化很简单，如:

var txt = @"<Commands>
    <Command command=""!command1"" response=""response1"" author=""niccon500"" count=""1237""/>
    <Command command=""!command2"" response=""response2"" author=""niccon500"" count=""1337""/>
    <Command command=""!command3"" response=""response3"" author=""niccon500"" count=""1437""/>
</Commands>";
CommandListXml commands;
using (var reader = new StringReader(txt))
{
    var serializer = new XmlSerializer(typeof(CommandListXml));
    commands = (CommandListXml)serializer.Deserialize(reader);
}

可以使用XDocument。方法加载文档，然后使用LINQ to XML语法创建命令列表:

XDocument doc = XDocument.Load(file_path);
var commands = doc.Root.Elements("Commands").Select(e => 
                      new Command()
                      {
                        command = e.Attribute("command").Value, 
                        response = e.Attribute("response").Value,
                        author = e.Attribute("author").Value, 
                        count= int.Parse(e.Attribute("count").Value) 
                      }).ToList();
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