XmlSerializer-将属性成员序列化为属性

我正在尝试将内部继承属性的所有成员序列化(XmlSerializer(为属性。

两个类：

public class Tree
{
    public Point Location { get; set; }
}
public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}

主程序：

AppleTree appleTree = new AppleTree
{
    Location = new Point(10, 20),
    FruitCount = 69
};
// Serialize ...

现在我得到这个：

<?xml version="1.0"?>
<AppleTree FruitCount="69">
  <Location>
    <X>10</X>
    <Y>20</Y>
  </Location>
</AppleTree>

但是我希望Location的所有成员都是AppleTree的属性。类似：

<?xml version="1.0"?>
<AppleTree FruitCount="69" X="10" Y="20" />

我知道，我可以这样做：

public class Tree
{
    [XmlIgnore]
    public Point Location { get; set; }
}
public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
    [XmlAttribute]
    public int X
    {
        get { return Location.X; }
        set { Location = new Point(value, Location.Y); }
    }
    [XmlAttribute]
    public int Y
    {
        get { return Location.Y; }
        set { Location = new Point(Location.X, value); }
    }
}

但我不希望所有属性都重复(这只是一个简单的例子(。

那么，还有其他解决方案吗？也许具有XmlSerializer的属性？

public class Tree
{
    [XmlIgnore]
    public Point Location { get; set;}
    [XmlAttribute]
    public double X { 
        get { return Location.X;} 
        set { Location = new Point(value, Location.Y); }
    }
    [XmlAttribute]
    public double Y { 
        get { return Location.Y;} 
        set { Location = new Point(Location.X, value); }
    }
}
public class AppleTree : Tree
{
    [XmlAttribute]
    public int FruitCount { get; set; }
}