c# XmlNode有祖先类型

本文关键字：类型 祖先 XmlNode | 更新日期: 2023-09-27 18:13:56

我有一个格式如下的XmlDocument。如果我执行以下搜索

XmlNode title = xmlDoc.SelectNodes("//Book/Title[contains(., '"Title3'")]");

我将得到一个XmlNode，它是一个标题。我怎样才能知道那本书是否属于出版物?我不总是假设title。parentnode。parentnode。parentnode存在。应该有一种直观的方式来表达:

if(title.hasAncestor("Publication") != null)
{
    // do whatever
}

任何帮助都将不胜感激

<Publications>
    <Novel>
        <Book>
            <Title>Title1</Title>
            <Author>Author1</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title2</Title>
            <Author>Author2</Author>
            <Year>2000</Year>
        </Book>
    </Novel>
    <History>
        <Book>
            <Title>Title3</Title>
            <Author>Author3</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title4</Title>
            <Author>Author4</Author>
            <Year>2000</Year>
        </Book>
    </History>
</Publications>
<StudyGuides>
    <Math>
        <Book>
            <Title>Title5</Title>
            <Author>Author5</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title6</Title>
            <Author>Author6</Author>
            <Year>2000</Year>
        </Book>
    </Math>
    <Science>
        <Book>
            <Title>Title7</Title>
            <Author>Author7</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title8</Title>
            <Author>Author8</Author>
            <Year>2000</Year>
        </Book>
    </Science>
</StudyGuides>

c# XmlNode有祖先类型

在XPath中可以使用ancestor轴:

//Book/Title[contains(., "Title3")][ancestor::Publications]

/Publications/*/Book/Title[contains(., 'Title3')]
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