是否有任何算法来验证澳大利亚的TFN号码?
本文关键字:TFN 号码 澳大利亚 验证 任何 算法 是否 | 更新日期: 2023-09-27 18:15:10
我们希望验证客户输入的澳大利亚TFN号码。有没有什么地方提到过官方的算法?
维基百科页面提到了一个简单的模11算法,但它似乎只是一个例子。
在Javascript中:
var tfn = $('#tfn').val();
//remove spaces and update
tfn = tfn.replace(/'s+/g, '');
$('#tfn').val(tfn);
//remove hyphens and update
tfn = tfn.replace(/[-]/g, '');
$('#tfn').val(tfn);
//validate only digits
var isNumber = /^[0-9]+$/.test(tfn);
if(!isNumber) {
return doError('Invalid TFN, only numbers are allowed.');
}
//validate length
var length = tfn.length;
if(length != 9) {
return doError('Invalid TFN, must have 9 digits.');
}
var digits = tfn.split('');
//do the calcs
var sum = (digits[0]*1)
+ (digits[1]*4)
+ (digits[2]*3)
+ (digits[3]*7)
+ (digits[4]*5)
+ (digits[5]*8)
+ (digits[6]*6)
+ (digits[7]*9)
+ (digits[8]*10);
var remainder = sum % 11;
if(remainder == 0) {
doSuccess('Valid TFN, hooray!');
} else {
return doError('Invalid TFN, check the digits.');
}
裁判:https://github.com/steveswinsburg/tfn-validator/blob/master/tfn-validator.html
在c#:
static void Main(string[] args)
{
int count = 0;
StringBuilder sb = new StringBuilder();
Random random = new Random();
while (count < 500000) {
int randomNumber = random.Next(100000000, 999999999);
if (ValidateTFN(randomNumber.ToString()))
{
sb.AppendLine(randomNumber.ToString());
count++;
}
}
System.IO.File.WriteAllText("TFNs.txt", sb.ToString());
}
public static bool ValidateTFN(string tfn)
{
//validate only digits
if (!IsNumeric(tfn)) return false;
//validate length
if (tfn.Length != 9) return false;
int[] digits = Array.ConvertAll(tfn.ToArray(), c => (int)Char.GetNumericValue(c));
//do the calcs
var sum = (digits[0] * 1)
+ (digits[1] * 4)
+ (digits[2] * 3)
+ (digits[3] * 7)
+ (digits[4] * 5)
+ (digits[5] * 8)
+ (digits[6] * 6)
+ (digits[7] * 9)
+ (digits[8] * 10);
var remainder = sum % 11;
return (remainder == 0);
}
public static bool IsNumeric(string s)
{
float output;
return float.TryParse(s, out output);
}
在Swift 5中:
确保使用键盘类型Number Pad来防止用户添加非数字字符。
func isTFNValid (tfn: String) -> Bool{
if (tfn.count != 9) {
return false
} else {
let characters = Array(tfn)
let digits = characters.map { Int(String($0))!}
//do the calcs
var sum = (digits[0]*1)
+ (digits[1]*4)
+ (digits[2]*3)
+ (digits[3]*7)
+ (digits[4]*5)
+ (digits[5]*8)
+ (digits[6]*6)
+ (digits[7]*9)
+ (digits[8]*10)
var remainder = sum % 11;
if(remainder == 0 && tfn.count == 9) {
return true
} else {
return false
}
}
}
感谢Jeremy Thompson的原创回答
支持Java 8和可能更高版本的实现
public class TFNUtils {
public static String format(String tfn) {
if (tfn == null) {
return null;
}
tfn = tfn.replaceAll("''s+","");
tfn = tfn.replaceAll("''-", "");
if (tfn.length() != 9) {
return null;
}
int sum = (Integer.parseInt(String.valueOf(tfn.charAt(0))))
+ (Integer.parseInt(String.valueOf(tfn.charAt(1)))*4)
+ (Integer.parseInt(String.valueOf(tfn.charAt(2)))*3)
+ (Integer.parseInt(String.valueOf(tfn.charAt(3)))*7)
+ (Integer.parseInt(String.valueOf(tfn.charAt(4)))*5)
+ (Integer.parseInt(String.valueOf(tfn.charAt(5)))*8)
+ (Integer.parseInt(String.valueOf(tfn.charAt(6)))*6)
+ (Integer.parseInt(String.valueOf(tfn.charAt(7)))*9)
+ (Integer.parseInt(String.valueOf(tfn.charAt(8)))*10);
if ((sum % 11) != 0){
return null;
}
StringBuilder tfnCompute = new StringBuilder(11);
tfnCompute.append(tfn.charAt(0));
tfnCompute.append(tfn.charAt(1));
tfnCompute.append(tfn.charAt(2));
tfnCompute.append('-');
tfnCompute.append(tfn.charAt(3));
tfnCompute.append(tfn.charAt(4));
tfnCompute.append(tfn.charAt(5));
tfnCompute.append('-');
tfnCompute.append(tfn.charAt(6));
tfnCompute.append(tfn.charAt(7));
tfnCompute.append(tfn.charAt(8));
return tfnCompute.toString();
}
public static boolean isValid(String tfn) {
return format(tfn) != null;
}
}
public class TFNUtilsTest {
@Test
public void testFormat() throws Exception {
assertEquals("123-456-782", TFNUtilsTest.format("123-456-782"));
assertEquals("123-456-782", TFNUtilsTest.format("123456782"));
assertEquals("123-456-782", TFNUtilsTest.format("123 456 782"));
// invaild returns null
assertNull(TFNUtilsTest.format("123 456 7829"));
assertNull(TFNUtilsTest.format("123 456 78"));
}
@Test
public void testIsValid() throws Exception {
assertTrue(TFNUtilsTest.isValid("123-456-782"));
assertTrue(TFNUtilsTest.isValid("123 456 782"));
assertFalse(TFNUtilsTest.isValid(null));
assertFalse(TFNUtilsTest.isValid(""));
assertFalse(TFNUtilsTest.isValid("123-456-780")); // invalid check-digit
assertFalse(TFNUtilsTest.isValid("123-456.782")); // invalid seperator
assertFalse(TFNUtilsTest.isValid("123-456-7820")); // > 9 digits
}
}
我检查了这篇文章中共享的c#代码,实际上使用该代码生成的TFN号码在提到的网站中无法进行TFN验证。因此,我在这个网站https://clearwater.com.au/code/tfn的帮助下提出了另一种解决方案来生成有效的TFN。
试试这个代码:
static void Main(string[] args)
{
int count = 0;
Random random = new Random();
while (count < 50)
{
int randomNumber = random.Next(100000000, 999999999);
// - Validate TFN - [START]
float output;
//validate only digits
string strRandomNumber = randomNumber.ToString();
if (!float.TryParse(strRandomNumber, out output))
{
Console.WriteLine("Invalid Input");
}
else
{
//validate length
if (strRandomNumber.Length != 9)
{
Console.WriteLine("Invalid Length");
}
else
{
int[] digits = Array.ConvertAll(strRandomNumber.ToArray(), c => (int)Char.GetNumericValue(c));
//do the calcs
var sum = (digits[0] * 10)
+ (digits[1] * 7)
+ (digits[2] * 8)
+ (digits[3] * 4)
+ (digits[4] * 6)
+ (digits[5] * 3)
+ (digits[6] * 5)
+ (digits[7] * 2)
+ (digits[8] * 1);
var remainder = sum % 11;
// - Validate TFN - [END]
if ((remainder == 0))
{
Console.WriteLine(randomNumber.ToString());
break;
}
}
}
count++;
}
}