根据c#中两个出生日期的星象之间的兼容性
本文关键字:出生日期 兼容性 之间 两个 根据 | 更新日期: 2023-09-27 17:52:13
我有一个关于我的小项目的问题,该项目是基于通过检查两个出生日期来检查两个占星之间的兼容性(例如:第一个人的出生日期(1-19(第一个数字代表月份,第二个数字代表日期)),然后相应地输入第二个人的工作。当我输入两个出生日期时,我的代码工作正常,这意味着它是根据出生日期告诉月份,日期和占星。但是,当我试图找到两个特定的星星之间的兼容性,它只计算第一个结果在if else语句,如果结果在第一个if else控制结构没有找到它不跳转到下一个else if语句,它直接跳转到最后一个else语句…我是第一次在这里张贴问题,请帮助我…如果有人可以这里是我的代码样本!!
DateTime date = Convert.ToDateTime(Console.ReadLine());
Console.WriteLine("Month:" + date.Month);
Console.WriteLine("Day:" + date.Day);
month = date.Month;
day = date.Day;
month1=date1.Month;
day1=date1.Day;
string[] stringArr = { "January", "February", "march", "April", "may", "June", "July", "august", "September", "October", "November", "December"};
switch (month)
{
case 1:
if (day <= 19)
return "Capricorn";
else
return "Aquarius";
case 2:
if (day <= 18)
return "Aquarius";
else
return "Pisces";
case 3:
if (day <= 20)
return "Pisces";
else
return "Aries";
case 4:
if (day <= 19)
return "Aries";
else
return "Taurus";
case 5:
if (day <= 20)
return "Taurus";
else
return "Gemini";
case 6:
if (day <= 20)
return "Gemini";
else
return "Cancer";
case 7:
if (day <= 22)
return "Cancer";
else
return "Leo";
case 8:
if (day <= 22)
return "Leo";
else
return "Virgo";
case 9:
if (day <= 22)
return "Virgo";
else
return "Libra";
case 10:
if (day <= 22)
return "Libra";
else
return "Scorpio";
case 11:
if (day <= 21)
return "Scorpio";
else
return "Sagittarius";
case 12:
if (day <= 21)
return "Sagittarius";
else
return "Capricorn";
return "";
}
另一个人的出生日期同时计算。
if (ob.month.Equals(1) && ob1.month1.Equals(1))
{
if (ob.day <= 19 && ob1.day1 <= 19)
{
Console.WriteLine("Compatibility of Capricon with Capricon");
}
// else if (ob.day <= 19 && ob1.day1 > 19)
else
{
Console.WriteLine("Compatibility of Capricon with Aquarius");
}
}
else if (ob.month.Equals(1) && ob.month1.Equals(2))
{
if (ob.day <= 19 && ob1.day1 <= 18)
{
Console.WriteLine("Compatibility of Capricon with Aquarius");
}
//else if (ob.day <= 19 && ob1.day1 > 18)
else
{
Console.WriteLine("Compatibility of Capricon with Pisces");
}
}
else if (ob.month.Equals(1) && ob.month1.Equals(3))
{
if (ob.day <= 19 && ob.day1 <= 20)
{
Console.WriteLine("Compatibility of Capricon with Pisces");
}
else
{
Console.WriteLine("Compatibility of Capricon with Aries");
}
}
else
{consle.writeLine("invalid");
}
这段代码只对第一个if else语句给出响应,而不是对其他if else语句。请帮助我,我该如何解决这个问题!!
你让事情变得很困难。让它更简单。
class Program
{
enum ZodiacSign
{
Aries, // March 21 - April 20
Taurus, // April 21 - May 21
Gemini, // May 22 - June 21
Cancer, // June 22 - July 22
Leo, // July 23 -August 21
Virgo, // August 22 - September 23
Libra, // September 24 - October 23
Scorpio, // October 24 - November 22
Sagittarius, // November 23 - December 22
Capricorn, // December 23 - January 20
Aquarius, // January 21 - February 19
Pisces // February 20- March 20
}
static ZodiacSign BirthdayToZodiacSign(DateTime birthday)
{
var periodEndList = new[] {
new { PeriodEnd = new DateTime(birthday.Year, 1, 20), ZodiacSign = ZodiacSign.Capricorn },
new { PeriodEnd = new DateTime(birthday.Year, 2, 19), ZodiacSign = ZodiacSign.Aquarius },
new { PeriodEnd = new DateTime(birthday.Year, 3, 20), ZodiacSign = ZodiacSign.Pisces },
new { PeriodEnd = new DateTime(birthday.Year, 4, 20), ZodiacSign = ZodiacSign.Aries },
new { PeriodEnd = new DateTime(birthday.Year, 5, 21), ZodiacSign = ZodiacSign.Taurus },
new { PeriodEnd = new DateTime(birthday.Year, 6, 21), ZodiacSign = ZodiacSign.Gemini },
new { PeriodEnd = new DateTime(birthday.Year, 7, 22), ZodiacSign = ZodiacSign.Cancer },
new { PeriodEnd = new DateTime(birthday.Year, 8, 21), ZodiacSign = ZodiacSign.Leo },
new { PeriodEnd = new DateTime(birthday.Year, 9, 23), ZodiacSign = ZodiacSign.Virgo },
new { PeriodEnd = new DateTime(birthday.Year, 10, 23), ZodiacSign = ZodiacSign.Libra },
new { PeriodEnd = new DateTime(birthday.Year, 11, 22), ZodiacSign = ZodiacSign.Scorpio },
new { PeriodEnd = new DateTime(birthday.Year, 12, 22), ZodiacSign = ZodiacSign.Sagittarius }
};
foreach (var periodEnd in periodEndList)
if (birthday <= periodEnd.PeriodEnd)
return periodEnd.ZodiacSign;
return ZodiacSign.Capricorn;
}
static string GenerateCompatibilityString(DateTime birthday1, DateTime birthday2)
{
return string.Format("Compatibility of {0} with {1}", BirthdayToZodiacSign(birthday1), BirthdayToZodiacSign(birthday2));
}
static void Main(string[] args)
{
Console.WriteLine(GenerateCompatibilityString(new DateTime(2014, 1, 1), new DateTime(2014, 6, 7)));
}
}
我还没有完全阅读你的代码(因为它似乎不完整,例如什么是ob
),但这里有一个一般性的评论:
如果你有一个if else-if
结构,那么只会执行一个分支。例如,在下面的例子中,只执行一个代码块(对应于第一个条件求值为true
的代码块):
if (condition1)
{}
else if (condition2)
{}
else if (condition3)
{}
else
{}
如果您有几个条件可以求值为true
,那么您应该使用多个if
语句来代替:
if (condition1)
{}
if (condition2)
{}
if (condition3)
{}
// if you need an "else" part:
if (!condition1 && !condition2 && !condition3)
{}
下面是一个简单的类来解决这个问题:
public class Signs
{
static List<string> SignList = new List<string>() {
"Capricorn", "Aquarius", "Pisces", "Aries", "Taurus", "Gemini", "Cancer", "Leo", "Virgo", "Libra", "Scorpio", "Sagittarius", "Capricorn", "Not Found" };
static List<int> StartDates = new List<int>() {
// month * 100 + day of month
120, 219, 320, 420, 521, 621, 722, 821, 923, 1023, 1122, 1222, 1232, 9999 // edge marker
};
static public string Sign(DateTime inDate)
{
return SignList[StartDates.TakeWhile(d => (inDate.Month*100)+inDate.Day > d).Count()];
}
}
这里有另一个版本可能更清楚https://stackoverflow.com/a/23183480/215752