Making GridView Visible
本文关键字:Visible GridView Making | 更新日期: 2023-09-27 18:15:48
我试图在windows 10通用应用程序中创建一个简单的弹出窗口。我创建了一个GridView
<GridView x:Name="PopUp" HorizontalAlignment="Left" Height="453" Margin="10,99,0,0" VerticalAlignment="Top" Width="340" Visibility="Collapsed">
<TextBox x:Name="Teacher" Height="29" TextWrapping="Wrap" Text="Teacher's name" Width="330"/>
<TextBox x:Name="Room" Height="29" TextWrapping="Wrap" Text="Room" Width="330"/>
<TextBox x:Name="Time" Height="29" TextWrapping="Wrap" Text="Time" Width="330"/>
<TextBox x:Name="Subject" Height="29" TextWrapping="Wrap" Text="Subject" Width="330"/>
<ComboBox x:Name="Day" HorizontalAlignment="Left" VerticalAlignment="Top" Width="330" />
<AppBarButton Icon="Cancel" Label="" Height="51" Margin="80,0,0,0"/>
<AppBarButton Icon="Accept" Label="" Height="48" Margin="-40,-70,0,0" BorderThickness="0"/>
</GridView>
我有按钮"添加"。我希望我的GridView在用户按下添加按钮时变得可见,而不是他在GridView中感觉字段,按下"Ok",GridView再次变得不可见。我使用了buttonclick事件,但它不起作用:
private void AppBarButton_Click(object sender, RoutedEventArgs e)
{
Popup pop = new Popup();
pop.Visibility = Visibility.Visible;
}
也许有另一种方式来创建一个弹出(或者我不知道它是怎么叫的)菜单,因为我不想创建单独的页面添加数据。
private void AppBarButton_Click(object sender, RoutedEventArgs e)
{
PopUp.Visibility = Visibility.Visible;
}
我希望这有助于你让我知道它是否可以;)