算出这些数字是否连续.例如:"5-6-7-8-9"，显示:"Consecutive&quo

本文关键字：quot 5-6-7-8-9 显示 Consecutive quo 连续 是否 例如 数字 | 更新日期: 2023-09-27 18:15:57

我正在做一个基本的字符串练习问题我的逻辑是这样的但很明显，我们不能增加像这样的字符串值temp++在我的情况下，它的解决方案应该是什么:

Console.WriteLine("Input a few numbers separated by a hyphen : ");
var input = Console.ReadLine();
var split = input.Split('-');
var temp = split[0];
for (int i = 1; i < split.Length; i++)
{
    temp++;
    Console.WriteLine(temp);
    if (temp == split[i])
    {
        Console.WriteLine("Consecutive");
    }
}

算出这些数字是否连续.例如:"5-6-7-8-9"，显示:"Consecutive&quo

你可以这样做:

static bool AreConsecutive(IReadOnlyList<int> numbers)
{
  for (var i = 1; i < numbers.Count; ++i)
  {
    if (numbers[i] != numbers[i - 1] + 1)
      return false;
  }
  return true;
}

你可以这样写:

Console.WriteLine("Input a few numbers separated by a hyphen : ");
var input = Console.ReadLine();
var inputParsed = input.Split('-').Select(int.Parse).ToList();
if (AreConsecutive(inputParsed))
  Console.WriteLine("Consecutive");

在错误输入(不能解析为整数的字符)的情况下，这不会给出令人愉快的消息。

我强烈建议不要使用var，当右边不能很明显地表明是什么类型。

让我用变量类型重写一下，看看是否能让问题更清楚:

Console.WriteLine("Input a few numbers separated by a hyphen : ");
string input = Console.ReadLine();
string[] split = input.Split('-');
// Think about what type this SHOULD be
string temp = split[0];
for (int i = 1; i < split.Length; i++)
{
    // Considering the fact that temp is actually currently a string, why should this work?
    // It's pretty obvious what "1" + 2 would mean, but what would "dog" + 1 mean?
    temp++;
    Console.WriteLine(temp);
    // Consider the fact that these must be the same type to do "==" (or there must be an implicit typecast between them)
    if (temp == split[i])
    {
        Console.WriteLine("Consecutive");
    }
}
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