将Json字符串反序列化为多个对象类型
本文关键字:对象 类型 Json 字符串 反序列化 | 更新日期: 2023-09-27 17:52:44
我有一个Json字符串,我从web服务;它有一个集合列表,每个集合代表一个对象,例如:
[ // Root List
[ // First Collection : Team Object
{
"id": 1,
"team_name": "Equipe Saidi",
"is_active": true,
"last_localisation_date": "2015-05-06T13:33:15+02:00"
},
{
"id": 3,
"team_name": "Equipe Kamal",
"is_active": true,
"last_localisation_date": "2015-05-06T09:22:15+02:00"
}
],
[// Second Collection : user Object
{
"id": 1,
"login": "khalil",
"mobile_password": "####",
"first_name": "Abdelali",
"last_name": "KHALIL",
"email": "KHALIL@gmail.com",
"role": "DR",
"is_active": true,
"charge": false
},
{
"id": 2,
"login": "ilhami",
"mobile_password": "####",
"first_name": "Abdellah",
"last_name": "ILHAMI",
"email": "ILHAMI@gmail.com",
"role": "DR",
"is_active": true,
"charge": false
}
]
]
我的实际代码(当然不能工作):
public async Task TeamsAndMobileUsers()
{
string data = "";
IList<User> MobileUsersList = new List<User>();
IList<Team> TeamsList = new List<Team>();
try
{
data = await GetResponse(PATH + TEAMS_USERS_URL);
TeamsList = JsonConvert.DeserializeObject<List<Team>>(data);
MobileUsersList = JsonConvert.DeserializeObject<List<User>>(data);
// Inserting
await SetAchievedActions(TeamsList);
}
catch (Exception e) {
_errors.Add(e.Message);
}
}
我使用Json.net和c#。我找不到解决方案,我读到我应该使用JsonReader并将其SupportMultipleContent属性设置为true,但我不知道如何实现该解决方案。
正如@YeldarKurmangaliyev已经说过的,你的json有两个不同的对象,我认为你可以这样做:
var j = JArray.Parse(data);
TeamsList = JsonConvert.DeserializeObject<List<Team>>(j[1].ToString());
MobileUsersList = JsonConvert.DeserializeObject<List<User>>(j[2].ToString());
您是否尝试过http://json2csharp.com/为该json生成合同类?此外,第一个和最后一个括号给出了无效的JSON
You need to create 4 classes
1st class TeamObject : Variable(id,team_name,is_active,last_localisation_date)
2nd class UserObject : Variable (id, login,mobile_password,first_name, last_name , email, role,is_active,charge)
3rd class RootList: Variable ( arraylist<TeamObject> obj, arraylist<UserObject > obj2)
4th class RootClass : Variable(arraylist<RootList> obj)
Gson gson=new Gson();
RootClass dtomodel = gson.fromJson(data , RootClass .class);
This parsing done using Gson Library