HttpClient将照片WITH消息发布到Facebook Graph
本文关键字:Facebook Graph 消息 照片 WITH HttpClient | 更新日期: 2023-09-27 18:16:59
问题
我正在尝试将一张照片与消息一起上传到Facebook API。
代码段-上传
requestUri = "https://graph.facebook.com/v2.0/me/photos?access_token=MyAccessToken"
var streamContent = new StreamContent(fileStream);
streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "'"files'"",
FileName = "'"image.jpg'""
};
streamContent.Headers.ContentType = new MediaTypeHeaderValue("image/jpeg");
var messageContent = new StringContent("message=HelloWorld");
var resultJson = webRequestClient.Post(requestUri, new MultipartFormDataContent()
{
messageContent,
streamContent,
});
代码-webRequestClient
public string Post(string uri, HttpContent postData)
{
return PostAsync(uri, postData).Result;
}
public async Task<string> PostAsync(string uri, HttpContent httpContent)
{
string resultStream;
using (var httpClient = new HttpClient())
{
var response = await httpClient.PostAsync(uri, httpContent);
response.EnsureSuccessStatusCode();
resultStream = await response.Content.ReadAsStringAsync();
}
return resultStream;
}
票据
- 如果我删除"messageContent":它会上传图片
- 如果我使用MultipartContent:它会上传图片,但会忽略我的"消息">
- 现在不要麻烦我为什么不使用异步功能
- 当它失败时,我会收到"糟糕"的请求
- 当我在requestUri中附加"message=helloworld"时,它是有效的,但这不是我的体系结构中处理这个问题的最灵活的解决方案
检查一下,它会解决你的问题,要么你必须通过流发送图像,然后你不需要明确地告诉类型是"images/jpeg"。
protected async void TakePictureAndUpload()
{
var ui = new CameraCaptureUI();
var file = await ui.CaptureFileAsync(CameraCaptureUIMode.Photo);
if (file != null)
{
byte[] myPicArray = await GetPhotoBytesAsync(file);
HttpClient httpClient = new HttpClient();
httpClient.BaseAddress = new Uri("http://yourdomainname.com");
MultipartFormDataContent form = new MultipartFormDataContent();
HttpContent content = new ByteArrayContent(myPicArray);
form.Add(content, "media", "filename.jpg");
content = new StringContent("my-username");
form.Add(content, "username");
HttpResponseMessage response = await httpClient.PostAsync("directory/my-site.php", form);
}
}
public async Task<byte[]> GetPhotoBytesAsync(StorageFile file)
{
IRandomAccessStream fileStream = await file.OpenAsync(FileAccessMode.Read);
var reader = new Windows.Storage.Streams.DataReader(fileStream.GetInputStreamAt(0));
await reader.LoadAsync((uint)fileStream.Size);
byte[] pixels = new byte[fileStream.Size];
reader.ReadBytes(pixels);
return pixels;
}