如何在.net中实现动态部分XML类序列化
本文关键字:XML 序列化 动态部 实现 net | 更新日期: 2023-09-27 18:17:00
我喜欢使用默认的。net xml序列化器将数据保存为简单的xml格式。我有一个enum MemberCode { feild1 = 1, feild2 = 2 /*...*/}
在运行时,我生成一个List<MemberCode>
的成员,我想保存到xml(有时更多,有时更少)。
如何实现这样的部分类序列化?
下面的代码可以解决您的问题。
创建一个可序列化的类MemberList,它包含一个MemberCodes数组。在运行时填充成员代码列表之后,我们将其转换为数组并将其序列化为XML。测试结果将被保存到debug文件夹中的test.xml文件中。
XML输出
<?xml version="1.0" encoding="utf-8"?>
<MemberList xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Members>
<Member>Field1</Member>
<Member>Field2</Member>
<Member>Field3</Member>
<Member>Field2</Member>
<Member>Field1</Member>
<Member>field4</Member>
</Members>
</MemberList>
代码:
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;
namespace ConsoleApplication1
{
public class Program
{
static void Main(string[] args)
{
// Your member code list
List<MemberCode> list = new List<MemberCode>();
// Add some members to the list during runtime (replace with your logic)
list.Add(MemberCode.Field1);
list.Add(MemberCode.Field2);
list.Add(MemberCode.Field3);
list.Add(MemberCode.Field2);
list.Add(MemberCode.Field1);
list.Add(MemberCode.field4);
// Create a new serializable member list
MemberList memberList = new MemberList();
// Convert your list to a serializable array
memberList.MemberCode = list.ToArray();
// Write the XML to a file
XmlSerializer serializer = new XmlSerializer(typeof(MemberList));
TextWriter writer = new StreamWriter("test.xml");
serializer.Serialize(writer, memberList);
Console.ReadLine();
}
}
[XmlRoot]
public class MemberList
{
[XmlArray("Members")]
[XmlArrayItem("Member", typeof(MemberCode))]
public MemberCode[] MemberCode { get; set; }
}
public enum MemberCode
{
Field1 = 1,
Field2 = 2,
Field3 = 3,
field4 = 4
}
}