xml反序列化—我得到0项,其中一些节点具有属性
本文关键字:节点 属性 反序列化 0项 xml | 更新日期: 2023-09-27 18:17:43
我这里有一个简化的XML示例
<?xml version="1.0" encoding="utf-8"?>
<node1>
<items>
<item>
<displayname>planet_one</displayname>
<atmosphere>
<part type="value">
<![CDATA[Hydrogen]]>
</part>
</atmosphere>
</item>
<item>
<displayname>planet_two</displayname>
<atmosphere>
<part type="value">
<![CDATA[Hydrogen]]>
</part>
<part type="value">
<![CDATA[Sulfur]]>
</part>
<part type="value">
<![CDATA[Acid]]>
</part>
</atmosphere>
</item>
</items>
</node1>
我不确定在消毒后,我一直得到零气氛?我不知道为什么,我试着改变我的代码,但我仍然得到零。下面是测试代码供您测试。
using System;
using System.Collections.Generic;
using System.Xml.Serialization;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string xml = "<?xml version='"1.0'" encoding='"utf-8'"?><node1><items><item><displayname>planet_one</displayname><atmosphere><part type='"value'"><![CDATA[Hydrogen]]></part></atmosphere></item><item><displayname>planet_two</displayname><atmosphere><part type='"value'"><![CDATA[Hydrogen]]></part><part type='"value'"><![CDATA[Sulfur]]></part><part type='"value'"><![CDATA[Acid]]></part></atmosphere></item></items></node1>";
var serialiser = new XmlSerializer(typeof(node1));
var streamXML = new System.IO.StringReader(xml);
var output = serialiser.Deserialize(streamXML);
node1 iData = (node1)output;
foreach (item n in iData.items)
{
Console.WriteLine(n.displayname);
Console.WriteLine("atmospheres count: " + n.atmosphere.Count);
}
Console.WriteLine("done");
Console.ReadLine();
}
}
public class node1
{
List<item> _items = new List<item>();
public List<item> items
{
get
{
return _items;
}
set
{
_items = value;
}
}
}
public class atmosphere
{
public string part { get; set; }
}
public class item
{
public string displayname { get; set; }
List<atmosphere> _atmosphere = new List<atmosphere>();
public List<atmosphere> atmosphere
{
get
{
return _atmosphere;
}
set
{
_atmosphere = value;
}
}
}
}
输出是
planet_one
atmospheres count: 0
planet_two
atmospheres count: 0
done
还是,问题是为什么是0 ?我错过什么了吗?
——update SOLVED——
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string xml = "<?xml version='"1.0'" encoding='"utf-8'"?><node1><items><item><displayname>planet_one</displayname><atmosphere><part type='"value'"><![CDATA[Hydrogen]]></part></atmosphere></item><item><displayname>planet_two</displayname><atmosphere><part type='"value'"><![CDATA[Hydrogen]]></part><part type='"value'"><![CDATA[Sulfur]]></part><part type='"value'"><![CDATA[Acid]]></part></atmosphere></item></items></node1>";
using (StreamReader reader = new StreamReader("d:''test.xml"))
{
xml = reader.ReadToEnd();
}
var serialiser = new XmlSerializer(typeof(node1));
var streamXML = new System.IO.StringReader(xml);
var output = serialiser.Deserialize(streamXML);
node1 iData = (node1)output;
foreach (item n in iData.items)
{
Console.WriteLine(n.displayname);
Console.WriteLine("atmospheres count: " + n.atmosphere.parts.Length);
foreach (string a in n.atmosphere.parts)
{
Console.WriteLine(" " + a);
}
Console.WriteLine("-------------'r'n");
}
Console.WriteLine("done");
Console.ReadLine();
}
}
public class node1
{
public item[] items { get; set; }
}
public class atmosphere
{
[XmlElement("part")]
public string[] parts { get; set; }
}
public class item
{
public string displayname { get; set; }
public atmosphere atmosphere { get; set; }
}
}
这是因为您的item
类中的属性atmosphere
应该是一个名为part
而不是atmosphere
的类的列表。该类应该包含type属性和内部数据:
public class item
{
public string displayname { get; set; }
List<part> _atmosphere = new List<part>();
public List<part> atmosphere
{
get
{
return _atmosphere;
}
set
{
_atmosphere = value;
}
}
}
public class part
{
[XmlAttribute]
public string type { get; set; }
string _data;
[XmlText]
public string Data
{
get { return _data; }
set { _data = value; }
}
}
如果你想让包含元素的类继续被命名为atmosphere
,你可以在atmosphere属性上使用属性[XmlArrayItem("part")]
(现在将是List<atmosphere>
类型),这样序列化器就知道xml中元素的名称是"part"而不是"atmosphere"(因为默认情况下它会期望元素的名称与类的名称相同):
public class item
{
public string displayname { get; set; }
List<atmosphere> _atmosphere = new List<atmosphere>();
[XmlArrayItem("part")]
public List<atmosphere> atmosphere
{
get
{
return _atmosphere;
}
set
{
_atmosphere = value;
}
}
}
public class atmosphere
{
[XmlAttribute]
public string type { get; set; }
string _data;
[XmlText]
public string Data
{
get { return _data; }
set { _data = value; }
}
}
当使用测试代码时,这两种方法都会给您预期的结果。