用c#解析复杂的JSON结果
本文关键字：JSON 结果 复杂 | 更新日期: 2023-09-27 18:18:37
我正在尝试解析以下复杂的JSON结果，这是从Zoho Crm API返回的:
{
"response":
{
"result":
{
"Contacts":
{
"row":
[
{
"no":"1",
"FL":
[
{
"content":"555555000000123456",
"val":"CONTACTID"
},
{
"content":"555555000000012345",
"val":"SMOWNERID"
},
{
"content":"John Doe",
"val":"Contact Owner"
},
{
"content":"Pete",
"val":"First Name"
},
{
"content":"Smith",
"val":"Last Name"
},
{
"content":"pete@mail.com",
"val":"Email"
},
{
"content":"5555551000000012346",
"val":"SMCREATORID"
},
{
"content":"Jane Doe",
"val":"Created By"
},
{
"content":"555555000000012347",
"val":"MODIFIEDBY"
},
{
"content":"Doris Doe",
"val":"Modified By"
},
{
"content":"2013-06-14 17:24:10",
"val":"Created Time"
},
{
"content":"2013-06-14 17:24:10",
"val":"Modified Time"
},
{
"content":"2013-06-14 17:28:05",
"val":"Last Activity Time"
}
]
},
{
...
}
]
}
},
"uri":"/crm/private/json/Contacts/getRecords"
}
}
下面是我的对象的样子:
public class Contact
{
[JsonProperty(PropertyName = "CONTACTID")]
public string ContactID { get; set; }
[JsonProperty(PropertyName = "SMOWNERID")]
public string OwnerID { get; set; }
[JsonProperty(PropertyName = "Contact Owner")]
public string ContactOwner { get; set; }
[JsonProperty(PropertyName = "First Name")]
public string FirstName { get; set; }
[JsonProperty(PropertyName = "Last Name")]
public string LasName { get; set; }
[JsonProperty(PropertyName = "Email")]
public string Email { get; set; }
[JsonProperty(PropertyName = "SMCREATORID")]
public string CreatorID { get; set; }
[JsonProperty(PropertyName = "Created By")]
public string CreatedBy { get; set; }
[JsonProperty(PropertyName = "MODIFIEDBY")]
public string ModifiedByID { get; set; }
[JsonProperty(PropertyName = "Modified By")]
public string ModifiedBy { get; set; }
[JsonProperty(PropertyName = "Created Time")]
public DateTime CreatedTime { get; set; }
[JsonProperty(PropertyName = "Modified Time")]
public DateTime ModifiedTime { get; set; }
[JsonProperty(PropertyName = "Last Activity Time")]
public DateTime LastActivityTime { get; set; }
}
"行"模式重复(no 1,2,3…)，所以我基本上想要得到的是这种类型的对象的通用列表。我正在尝试使用JSON。. NET，但我愿意接受其他建议，如果它能使这更容易。
显然在这种情况下不起作用:
var response = JsonConvert.DeserializeObject<Contact>(jsonString);
var deserializedObjects = JsonConvert.DeserializeObject<List<Contact>>(jsonString);
这里是一个解决方案，我把它放在一起使用JavaScriptSerializer来解析这个，但它是迄今为止我最糟糕的代码块之一!
List<Contact> loContactList = new List<Contact>();
Contact loContact = null;
Dictionary<string, object> dictionary = new JavaScriptSerializer().Deserialize<Dictionary<string, object>>(jsonString);
var response = (Dictionary<string, object>)dictionary["response"];
var result = (Dictionary<string, object>)response["result"];
var contacts = (Dictionary<string, object>)result["Contacts"];
var row = (ArrayList)contacts["row"];
foreach (var item in row)
{
var loArrayItem = (Dictionary<string, object>)item;
var fl = (ArrayList)loArrayItem["FL"];
loContact = new Contact();
foreach (var contactitem in fl)
{
var contactdict = (Dictionary<string, object>)contactitem;
string val = (string)contactdict["val"];
string content = (string)contactdict["content"];
if (val == "CONTACTID")
{
loContact.ContactID = content;
}
else if (val == "SMOWNERID")
{
loContact.OwnerID = content;
}
else if (val == "Contact Owner")
{
loContact.ContactOwner = content;
}
else if (val == "First Name")
{
loContact.FirstName = content;
}
else if (val == "Last Name")
{
loContact.LastName = content;
}
else if (val == "Email")
{
loContact.Email = content;
}
else if (val == "SMCREATORID")
{
loContact.CreatorID = content;
}
else if (val == "Created By")
{
loContact.CreatedBy = content;
}
else if (val == "MODIFIEDBY")
{
loContact.ModifiedByID = content;
}
else if (val == "Modified By")
{
loContact.ModifiedBy = content;
}
else if (val == "Created Time")
{
loContact.CreatedTime = Convert.ToDateTime(content);
}
else if (val == "Modified Time")
{
loContact.ModifiedTime = Convert.ToDateTime(content);
}
else if (val == "Last Activity Time")
{
loContact.LastActivityTime = Convert.ToDateTime(content);
}
}
loContactList.Add(loContact);
}
我在StackOverflow上看过其他类似的帖子，似乎没有一个能解决这个问题。有人能解决这个问题吗?我的目标是以一种更优雅的方式解析这个JSON响应，它不涉及一百万个字典对象和ArrayList!如有任何帮助，不胜感激。
谢谢,皮特
更新7/2/13:
根据Manvik的建议，我整理了以下附加的解决方案:
public class ResponseActual
{
[JsonProperty("response")]
public Response2 Response { get; set; }
}
public class Response2
{
[JsonProperty("result")]
public Result Result { get; set; }
[JsonProperty("uri")]
public string Uri { get; set; }
}
public class Result
{
[JsonProperty("Contacts")]
public Contacts Contacts { get; set; }
}
public class Contacts
{
[JsonProperty("row")]
public IList<Row> Row { get; set; }
}
public class Row
{
[JsonProperty("no")]
public string No { get; set; }
[JsonProperty("FL")]
public IList<FL> FL { get; set; }
}
public class FL
{
[JsonProperty("content")]
public string Content { get; set; }
[JsonProperty("val")]
public string Val { get; set; }
}
List<Contact> loContactList = new List<Contact>();
Contact loContact = null;
ResponseActual respone = JsonConvert.DeserializeObject<ResponseActual>(jsonString);
foreach (var row in respone.Response.Result.Contacts.Row)
{
loContact = new Contact();
var rowItem = row.FL.ToList();
try { loContact.ContactID = rowItem.Where<FL>((s, t) => s.Val == "CONTACTID").Select(x => x.Content).Single(); }
catch { }
try { loContact.OwnerID = rowItem.Where<FL>((s, t) => s.Val == "SMOWNERID").Select(x => x.Content).Single(); }
catch { }
try { loContact.ContactOwner = rowItem.Where<FL>((s, t) => s.Val == "Contact Owner").Select(x => x.Content).Single(); }
catch { }
try { loContact.FirstName = rowItem.Where<FL>((s, t) => s.Val == "First Name").Select(x => x.Content).Single(); }
catch { }
try { loContact.LastName = rowItem.Where<FL>((s, t) => s.Val == "Last Name").Select(x => x.Content).Single(); }
catch { }
try { loContact.Email = rowItem.Where<FL>((s, t) => s.Val == "Email").Select(x => x.Content).Single(); } catch { }
try { loContact.CreatorID = rowItem.Where<FL>((s, t) => s.Val == "SMCREATORID").Select(x => x.Content).Single(); }
catch { }
try { loContact.CreatedBy = rowItem.Where<FL>((s, t) => s.Val == "Created By").Select(x => x.Content).Single(); }
catch { }
try { loContact.ModifiedByID = rowItem.Where<FL>((s, t) => s.Val == "MODIFIEDBY").Select(x => x.Content).Single(); }
catch { }
try { loContact.ModifiedBy = rowItem.Where<FL>((s, t) => s.Val == "Modified By").Select(x => x.Content).Single(); }
catch { }
try { loContact.CreatedTime = Convert.ToDateTime(rowItem.Where<FL>((s, t) => s.Val == "Created Time").Select(x => x.Content).Single()); }
catch { }
try { loContact.ModifiedTime = Convert.ToDateTime(rowItem.Where<FL>((s, t) => s.Val == "Modified Time").Select(x => x.Content).Single()); }
catch { }
try { loContact.LastActivityTime = Convert.ToDateTime(rowItem.Where<FL>((s, t) => s.Val == "Last Activity Time").Select(x => x.Content).Single()); }
catch { }
loContactList.Add(loContact);
}
使用以下类使用JSON进行反序列化。净
public class ResponseActual
{
[JsonProperty("response")]
public Response2 Response { get; set; }
}
public class Response2
{
[JsonProperty("result")]
public Result Result { get; set; }
[JsonProperty("uri")]
public string Uri { get; set; }
}
public class Result
{
[JsonProperty("Contacts")]
public Contacts Contacts { get; set; }
}
public class Contacts
{
[JsonProperty("row")]
public IList<Row> Row { get; set; }
}
public class Row
{
[JsonProperty("no")]
public string No { get; set; }
[JsonProperty("FL")]
public IList<FL> FL { get; set; }
}
public class FL
{
[JsonProperty("content")]
public string Content { get; set; }
[JsonProperty("val")]
public string Val { get; set; }
}
//To De-serialize
ResponseActual respone = JsonConvert.DeserializeObject<ResponseActual>(jSON_sTRING)
//Get the contacts list
List<FL> contacts = respone.Response.Result.Contacts.Row[0].FL.ToList();
//Now Get the required value using LINQ
var value = contacts.Where<FL>((s, e) => s.Val =="Email").Select(x=>x.Content).Single();
你也可以签出这个-使用Newtonsoft(或LINQ到JSON)将JSON反序列化到。net对象
您需要在反序列化对象中包含以下JSON部分类型:
{
"response":
{
"result":
{
"Contacts":
{
"row":
[
{
"no":"1",
"FL":
类类型:'Contact'是不合适的。
you can use this code:
dynamic dictionary = (JsonConvert.DeserializeObject>(jsonstring))["response"];
var result = dictionary.result;
var contact= result.Contacts;
var row= contact.row;
foreach (var item in row)
{
var no= item.no;
}
我可以问你一件事吗?导出JSON的是你吗?我问这个问题是因为格式很奇怪，它确实妨碍了你的代码。
一种更简单的格式将允许您以非常直接的方式序列化字符串。