C#类和结构

本文关键字:结构 | 更新日期: 2023-09-27 18:19:48

我在C中的序列化有一些问题#拥有代码:

public struct CoOrds
{
    public double x, y, z;
    public CoOrds(double p1, double p2, double p3)
    {
        x = p1;
        y = p2;
        z = p3;
    }
}
public struct printColor
{
    public int r, g, b;
    public printColor(int p1, int p2, int p3)
    {
        r = p1;
        g = p2;
        b = p3;
    }
}
[Serializable]
public abstract class shape : ISerializable
{
    public int borderStyle=1;        
    /*  ===============================COLOR PARAMETERS================================ */
    public printColor colorRGB = new printColor(0, 0, 0);

    public System.Drawing.Drawing2D.DashStyle styleLine { get; set; }
    public int widht=2;
    /*=================================FILL PARAMETERS=====================================*/
    public printColor fillColorRGB = new printColor(255,255, 255);
    public shape()
    {
    }
    protected shape(SerializationInfo info, StreamingContext context)
    {
        colorRGB.r = info.GetInt32("colorLine.r");
        colorRGB.g = info.GetInt32("colorLine.g");
        colorRGB.b = info.GetInt32("colorLine.b");
        borderStyle = info.GetInt32("borderStyle");
        fillColorRGB.r = info.GetInt32("fillColorRGB.r");
        fillColorRGB.g = info.GetInt32("fillColorRGB.g");
        fillColorRGB.b = info.GetInt32("fillColorRGB.b");
        widht = info.GetInt32("widht");
    }
    public virtual void GetObjectData(SerializationInfo info, StreamingContext context)
    {
        info.AddValue("colorLine.r",colorRGB.r);
        info.AddValue("colorLine.g", colorRGB.g);
        info.AddValue("colorLine.b", colorRGB.b);
        info.AddValue("borderStyle",borderStyle);
        info.AddValue("fillColorRGB.r", fillColorRGB.r);
        info.AddValue("fillColorRGB.g", fillColorRGB.g);
        info.AddValue("fillColorRGB.b", fillColorRGB.b);
        info.AddValue("widht", widht);
    }
 .....

1.如何像一样序列化结构

[Serializable]
public struct CoOrds

在类下,以及如何将其放入shape和GetObjectData中,因为我有太多的类必须使用这个结构

Thx

C#类和结构

您可以直接用info.AddValue("Pos", pos, typeof(CoOrds)序列化它,也可以转换为string

[Serializable()]
public struct Coords
{
    readonly public double x, y, z;
    public Coords(double x, double y, double z)
    {
        this.x = x;
        this.y = y;
        this.z = z;
    }
    public static Coords FromString(string value)
    {
        if (string.IsNullOrEmpty(value)) return new Coords();
        double x = 0,y= 0,z = 0;
        string[] parts = value.Split(',');
        if (parts.Length > 0) double.TryParse(parts[0], out x);
        if (parts.Length > 1) double.TryParse(parts[1], out y);
        if (parts.Length > 2) double.TryParse(parts[2], out z);
        return new Coords(x, y, z);
    }
    public override string ToString()
    {
        //Ensure round-trip formatting
        return string.Format("{0:R},{1:R},{2:R}", x, y, z);
    }
}

然后用将其序列化

[Serializable()]
public class Vertex : ISerializable
{
    public Coords pos1, pos2;
    ...
    public void GetObjectData(SerializationInfo info, StreamingContext context)
    {
        info.AddValue("Pos1", pos1.ToString());
        info.AddValue("Pos2", pos2, typeof(Coords));
    }
    public Vertex(SerializationInfo info, StreamingContext context)
    {
        this.pos1 = Coords.FromString(info.GetValue("Pos1", typeof(string)) as string);
        this.pos2 = (Coords)info.GetValue("Pos2", typeof(Coords));
    }
}

与工作一样好的测试代码,我做了。