如何设置列表的属性<；类>；在C#中

本文关键字：lt gt 属性 何设置 设置 列表 | 更新日期: 2023-09-27 18:19:50

我有一个这样定义的类：

[DataContract]
public class Response2
{
    [DataMember(Name = "done")]
    public bool done;
    [DataMember(Name = "records")]
    public List<Response3> r3entry;
}
[DataContract]
public class Response3
{
    [DataMember(Name = "Id")]
    public string strId { get; set; }
    [DataMember(Name = "Name")]
    public string strName { get; set; }
}

现在，我想做的是从另一个类中获取值并填充。。。像这样的东西：

string propertyRequest2 = CreatePropertyRequest2();
Response2 propResponse2 = MakeRequest2(propertyRequest2, sfToken);
List<Response> listAllData = new List<Response>();
foreach (var responseEntry in propResponse2.r3entry)
{
    listAllData.Add(new Response() { strId = responseEntry.strId, strName = responseEntry.strName } );
    // NOTE .strId IS ALWAYS UNIQUE IN BOTH CLASSES
    // - I know this is NOT the right syntax... will fix later.
    Where listAllData.strId = responseEntry.strId
    {
        listAllData.property = propertyResponse2(.strId=responseEntry.strId).property
    }
}

我确信（至少）代码的最后一部分对大多数阅读本文的人来说是痛苦的，但我会修复它，这样就不那么可怕了。我只是不知道是否解释得那么清楚。万一我错了，这里的重点更像是：

// WE HAVE A LIST OF CLASSES WITH PROPERTIES
// ASSUME PROPERTIES ARE ID, ITEM, NAME
LIST1 = { ("1", "A", "APPLE"), ("2", "B", "BANANA"), ("3", "C", "COCONUT")}
// NOW WE HAVE ANOTHER LIST THAT HAS THE SAME ID BUT DIFF DATA
// ASSUME PROPERTIES ARE ID, COLOR
LIST2 = { ("1", "RED"), ("2", "YELLOW"), ("3", "BROWN) }
// AND THEN I WANT TO CREATE A NEW LIST WITH BOTH SETS OF DATA COMBINED
// ASSUME PROPERTIES ARE ID, ITEM, NAME, COLOR
LIST3 = { ("1", "A", "APPLE", "RED"), ("2", "B", "BANANA"), ("3", "C", "COCONUT", "BROWN") }

有什么想法吗？

如何设置列表的属性<；类>；在C#中

带投影的内部连接：

var list = from l1 in LIST1
    join l2 in LIST2 on l1.ID equals l2.ID
    select new {
        l1.ID,
        l1.Item,
        l1.Name,
        l2.Color
    }
    .ToList()

在不知道目标的情况下，Zip函数对两个列表执行操作，并返回这两个列表的乘积。你可以在这里阅读更多信息：

MSDN 上的Zip

但实际上，如果你有两个清单，比如说：

int[] numbers = { 1, 2, 3, 4 };
string[] words = { "one", "two", "three" };
// The following example concatenates corresponding elements of the
// two input sequences.
var numbersAndWords = numbers.Zip(words, (first, second) => first + " " + second);

所以在你的情况下，它可能是这样的：

Response2[] response2 = //some list
Response3[] response3= // some other list
var response2Andresponse3 = response2.Zip(response3, (res2,res3) => //something you want to do with them

这将使response2的第一个元素与response3的第一个元件配对，依此类推。我们还在这里假设它们具有相同的长度，这样就不会有未配对的属性。

您必须找到一种方法来将其输出到您可能会发现有用的东西，但您会有一个列表，其中它们逐元素对应。

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