嵌套大括号内数据的Regex

本文关键字：数据 Regex 嵌套 | 更新日期: 2023-09-27 18:21:21

我有以下数据记录：

@INPROCEEDINGS{conf/icsm/Ceccato07,
  author = {Mariano Ceccato},
  title = {Migrating Object Oriented code to Aspect Oriented Programming},
  booktitle = {ICSM},
  year = {2007},
  pages = {497--498},
  publisher = {IEEE},
  bibdate = {2008-11-18},
  bibsource = {DBLP, http://dblp.uni-trier.de/db/conf/icsm/icsm2007.html#Ceccato07},
  crossref = {conf/icsm/2007},
  owner = {Administrator},
  timestamp = {2009.04.30},
  url = {http://dx.doi.org/10.1109/ICSM.2007.4362668}
}

有没有一种方法可以让我得到下面的匹配，这样每一行都是一个单独的匹配

  conf/icsm/Ceccato07
  author = Mariano Ceccato
  title = Migrating Object Oriented code to Aspect Oriented Programming
  booktitle = ICSM
  year = 2007
  pages = 497--498
  publisher = IEEE
  bibdate = 2008-11-18
  bibsource = DBLP, http://dblp.uni-trier.de/db/conf/icsm/icsm2007.html#Ceccato07
  crossref = conf/icsm/2007
  owner = Administrator
  timestamp = 2009.04.30
  url = http://dx.doi.org/10.1109/ICSM.2007.4362668

这是我的模式，它错过了第一行匹配，并且没有去掉大括号和逗号

string pattern = ".*[{].*}";

嵌套大括号内数据的Regex

这个正则表达式在Singleline模式下，将获取两个外部大括号内的所有内容：

(?<='{).*(?='})

然后你可以用C#去掉内部支架：

var regex = new Regex(@"(?<='{).*(?='})", RegexOptions.Singleline);
var match = regex.Match(input);
return match.Value.Replace("{", string.Empty).Replace("}", string.Empty);
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