家庭作业-有点像:/双字符串prolem

本文关键字：字符串 prolem 家庭作业 | 更新日期: 2023-09-27 18:22:33

我收到了这项家庭作业，搞不明白。我需要询问用户他想输入多少城镇名称。例如5。然后，他输入5个城镇名称。然后，我们需要找到名字的平均长度，并向他展示字母少于平均长度的名字。感谢您的共享时间：）到目前为止我的代码：

static void Main(string[] args)
{
    int n;
    Console.WriteLine("How many town names would you like to enter:");
    n = int.Parse(Console.ReadLine());
    string[] TownNames = new string[n];
    Console.Clear();
    Console.WriteLine("Enter {0} town names:", n);
    for (int i = 0; i < n; i++)
    {
        Console.Write("Enter number {0}: ", i + 1);
        TownNames[i] = Convert.ToString(Console.ReadLine());
    }
    Console.ReadKey(true);
}
static void Average(double[] TownNames, int n)
{
}

家庭作业-有点像:/双字符串prolem

你走在了正确的轨道上。主方法中有一个数组，用用户输入的城镇名称填充该数组。我将把这两个标准分成不同的方法：

int FindAverage(string[] towns);
IEnumerable<string> FilterShortNamedTowns(string[] towns, int average);

平均应该很容易。您只需要根据字符串类公开的Length属性计算平均值。此属性跟踪字符串中的字符数。

private static int FindAverage(string[] towns)
{
   int totalLength = 0;
   foreach(var town in towns)
      totalLength += town.Length;
   return totalLength / towns.Length;
   // This can be shortened to the following use LINQ but the above shows the algorithm better.
   // return towns.Select(town => town.Length).Average();
}

第二种方法应该只是再次循环通过集合，并且只返回Length<平均的

private static IEnumerable<string> FilterShortNamedTowns(string[] towns, int average)
{
   return towns.Where(town => town.Length < average);
}

要找到名称的平均长度，必须将所有名称的长度相加。然后除以名字的数目。

int n;
Console.WriteLine("How many town names would you like to enter:");
n = int.Parse(Console.ReadLine());
string[] TownNames = new string[n];
Console.Clear();
int totalLength = 0; // holds total length of names
Console.WriteLine("Enter {0} town names:", n);
for (int i = 0; i < n; i++)
{
    Console.Write("Enter number {0}: ", i + 1);
    TownNames[i] = Convert.ToString(Console.ReadLine());
    totalLength += TownNames[i].Length; // add the name length to total
}
int average = totalLength/n; // calculate average
Console.Clear();
Console.WriteLine("town names lower than average length:");
for (int i = 0; i < n; i++)
{
    if (TownNames[i].Length < average) // print values when the length name is less than average.
    {
        Console.WriteLine("Town {0} : {1}", i + 1, TownNames[i]);
    }
}

Console.ReadKey(true);
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