如何调试XML反序列化
本文关键字:XML 反序列化 调试 何调试 | 更新日期: 2023-09-27 18:23:59
我想知道您是否有关于如何调试以下XML反序列化的提示?我不能让它工作。反序列化程序基本上创建了调用和斜杠实例,但它们的所有属性都是空的。到的相关类别如下所示。
带有反序列化程序的SkillCollection类:
[DataContract(Name = "Skills", Namespace = "")]
public class SkillCollection
{
[DataMember(Name = "Slash")]
public Skill Slash { get; set; }
[DataMember(Name = "Summon")]
public Skill Summon { get; set; }
public static object Deser(string path, Type toType)
{
var s = new DataContractSerializer(toType);
using (FileStream fs = File.Open(path, FileMode.Open))
{
object s2 = s.ReadObject(fs);
if (s2 == null)
Console.WriteLine(@" Deserialized object is null");
else
Console.WriteLine(@" Deserialized type: {0}", s2.GetType());
return s2;
}
}
它是通过属性Skills:从另一个类调用的
Skills = (SkillCollection)SkillCollection.Deser(
Path.Combine(path, "Skills.xml"),
typeof(SkillCollection));
技能等级:
public class Skill
{
//Cast: time it takes to cast it
[DataMember(Name = "Cast")]
public float Cast { get; set; }
//ReCast: cooldown period before player can cast it again
[DataMember(Name = "ReCast")]
public float ReCast { get; set; }
[DataMember(Name = "MPCost")]
public int MpCost { get; set; }
public Timer Timer { get; private set; }
public bool Ready { get; set; }
public Skill()
{
Ready = true;
Timer = new Timer { Interval = ReCast + 500, AutoReset = false };
Timer.Elapsed += OnTimedEvent;
}
//Runs when recast is up
private void OnTimedEvent(object source, ElapsedEventArgs e)
{
Ready = true;
}
}
XML文件:
<Skills>
<Slash>
<Cast>0.00</Cast>
<ReCast>60.00</ReCast>
<MPCost>0</MPCost>
</Slash>
<Summon>
<Cast>5.98</Cast>
<ReCast>2.49</ReCast>
<MPCost>0</MPCost>
</Summon>
</Skills>
为了避免混淆,我的目标是运行反序列化程序,然后让SkillCollection类包含Skill的两个实例(Slash和Summon),并能够通过它们的属性分别访问它们。
感谢您提供的任何调试帮助/提示。
安德斯,
我最近做了一项类似的任务。查看您的代码,您似乎将DataContract名称和命名空间设置错了。在Skill类和SkillCollection类之上都需要指定:[DataContract(Name = "Skills", Namespace = "")]
。这对于"允许"序列化程序输入Properties至关重要。请记住,仅仅将其设置在SkillCollection类之上是不够的。
编辑:我最初以为你可以省略Namespace
,但你不能。如果您没有在XML中指定名称空间,则必须将其设置为Namespace=""
,如果您指定了名称空间,那么必须将其设为指定的名称空间。
此外,调试它的一种方法是将Deser方法更改为:
public static object Deserialize(string path, Type toType)
{
using (var sr = new FileStream(path, FileMode.Open))
{
SkillCollection p = null;
XmlDictionaryReader reader = XmlDictionaryReader.CreateTextReader(sr, new XmlDictionaryReaderQuotas());
var serializer = new DataContractSerializer(toType);
while (reader.Read())
{
switch (reader.NodeType)
{
case XmlNodeType.Element:
if (serializer.IsStartObject(reader))
{
Console.WriteLine(@"Found the element");
p = (SkillCollection)serializer.ReadObject(reader);
Console.WriteLine("{0} {1} id:{2}",
p.Slash.ToString(), p.Summon.ToString());
}
Console.WriteLine(reader.Name);
break;
}
}
return p;
}
}