数组的 C# XML 反序列化
本文关键字:反序列化 XML 数组 | 更新日期: 2023-09-27 18:30:17
>我有一个关于反序列化数组的问题。Becouse 数组元素可以是各种类型的。您可以看到以下示例:
<?xml version="1.0" encoding="UTF-8"?><export xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://zakupki.gov.ru/oos/export/1" xmlns:oos="http://zakupki.gov.ru/oos/types/1">
<notificationZK>
... item 1 data
</notificationZK>
<notificationZK>
... item 2 data
</notificationZK>
<notificationFF>
... item 3 data
</notificationFF>
</export>
所有元素都扩展notificationType
[System.Xml.Serialization.XmlIncludeAttribute(typeof(notificationSZType))]
[System.Xml.Serialization.XmlIncludeAttribute(typeof(notificationPOType))]
[System.Xml.Serialization.XmlIncludeAttribute(typeof(notificationZKType))]
[System.Xml.Serialization.XmlIncludeAttribute(typeof(notificationEFType))]
[System.Xml.Serialization.XmlIncludeAttribute(typeof(notificationOKType))]
public partial class notificationType
{
...
所以问题是我如何从我的 XML 文件中获取notificationType
元素的集合?我想我不能做这样的事情
[Serializable()]
[System.Xml.Serialization.XmlRoot("export")]
public class NotificationCollection
{
[XmlArray("")] // ???? what I need write here?
[XmlArrayItem("", typeof(notificationType))] // ??? and here?
public notificationType[] notification { get; set; }
}
问候!
添加-------------
所以。我做这个:
[Serializable()]
[System.Xml.Serialization.XmlRoot("export")]
public class NotificationCollection
{
[XmlElement("notificationSZType", Type = typeof(notificationSZType))]
[XmlElement("notificationPOType", Type = typeof(notificationPOType))]
[XmlElement("notificationZKType", Type = typeof(notificationZKType))]
[XmlElement("notificationEFType", Type = typeof(notificationEFType))]
[XmlElement("notificationOKType", Type = typeof(notificationOKType))]
public notificationType[] notification { get; set; }
}
class Program
{
static void Main(string[] args)
{
NotificationCollection collection = null;
string path = @"E:'notification.xml";
XmlSerializer serializer = new XmlSerializer(typeof(notificationType));
StreamReader reader = new StreamReader(path);
collection = (NotificationCollection) serializer.Deserialize(reader);
reader.Close();
}
}
但有 System.InvalidOperationException 在serializer.Deserialize(reader);
时未处理
Message=<export xmlns='http://zakupki.gov.ru/oos/export/1'> not expected.
我做错了什么?
如何将类型声明移动到集合中?
[XmlRoot("export")]
public class NotificationCollection
{
[XmlElement("notificationZK", typeof(NotificationTypeZK))]
[XmlElement("notificationFF", typeof(NotificationTypeFF))]
public List<NotificationType> Notifications { get; set; }
}
public class NotificationType
{
}
public class NotificationTypeZK : NotificationType { }
public class NotificationTypeFF : NotificationType { }
static void Main(string[] args)
{
var data = @"<export><notificationZK /><notificationZK /><notificationFF /></export>";
var serializer = new XmlSerializer(typeof(NotificationCollection));
using (var reader = new StringReader(data))
{
var notifications = serializer.Deserialize(reader);
}
}
这应该可以完成这项工作
[Serializable()]
[System.Xml.Serialization.XmlRoot("export")]
public class NotificationCollection
{
[XmlElement("notificationSZType", Type = typeof(notificationSZType))]
[XmlElement("notificationPOType", Type = typeof(notificationPOType))]
[XmlElement("notificationZKType", Type = typeof(notificationZKType))]
[XmlElement("notificationEFType", Type = typeof(notificationEFType))]
[XmlElement("notificationOKType", Type = typeof(notificationOKType))]
public notificationType[] notification { get; set; }
}
这个问题对我来说
也很有趣。我编写了简化的应用程序来实现您的要求:
[Serializable]
[XmlInclude(typeof(ItemA))]
[XmlInclude(typeof(ItemB))]
public class BaseItem
{
public bool Value { get; set; }
}
[Serializable]
public class ItemA : BaseItem
{
public string Text { get; set; }
}
[Serializable]
public class ItemB : BaseItem
{
public int Number { get; set; }
}
[Serializable]
public class ItemsArray
{
public BaseItem[] Items { get; set; }
}
class Program
{
static void Main(string[] args)
{
var array = new ItemsArray
{
Items = new BaseItem[]
{
new ItemA { Value = true, Text = "Test" },
new ItemB { Value = false, Number = 7 }
}
};
ItemsArray output;
using (var stream = new MemoryStream())
{
var serializer = new XmlSerializer(typeof(ItemsArray));
serializer.Serialize(stream, array);
stream.Position = 0;
output = (ItemsArray)serializer.Deserialize(stream);
}
}
}
反序列化后,我们得到的正是我们序列化的内容。流中的 XML 如下所示:
<?xml version="1.0"?>
<ItemsArray xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Items>
<BaseItem xsi:type="ItemA">
<Value>true</Value>
<Text>Test</Text>
</BaseItem>
<BaseItem xsi:type="ItemB">
<Value>false</Value>
<Number>7</Number>
</BaseItem>
</Items>
</ItemsArray>
正如其他答案中提到的,您不能在 XML 数组中使用不同的标记。但是,仍然可以存储不同的类型。序列化程序通过使用 xsi:type
属性执行此操作。
为了解决您的问题,您可能需要使用另一种XML方案。