反序列化 XML 包含对象列表到对象列表
本文关键字:对象 列表 包含 XML 反序列化 | 更新日期: 2023-09-27 18:37:07
我正在尝试将对象列表保存到xml文件中。但是当我保存一次时,它会删除保存前的。我的意思是,如果我保存在"雷达"的 xml 文件 1 列表上,而不是保存在"观察者"的保存 xml 文件列表中,它只会保存我保存的最后一个列表。有什么方法可以拯救他们两个吗?我的代码保存:
XmlSerializer serializer = new XmlSerializer(typeof(List<Observer>));
using (TextWriter writer = new StreamWriter(@"C:'Users'user'Desktop'MapSample'bin'Debug'ListObserver.xml"))
{
serializer.Serialize(writer, list);
}
希望你能理解。谢谢建议。
编辑:我创建了包含列表作为属性的新对象。现在所有列表都在一个 xml 文件中。对象 :
[Serializable()]
public class SaveObject
{
public List<Radar> listRadars = new List<Radar>();
public List<Ikun> listIkuns = new List<Ikun>();
public List<Observer> listObservers = new List<Observer>();
public XmlSerializer ser;
public SaveObject(List<Observer> listObservers, List<Ikun> listIkuns,List<Radar> listRadars)
{
this.listIkuns = listIkuns;
this.listRadars = listRadars;
this.listObservers = listObservers;
}
public SaveObject()
{
ser = new XmlSerializer(this.GetType());
}
}
序列化函数:
public void Serialize(SaveObject SO)
{
if (IfPathToSave) // Select save - not auto !
{
XmlSerializer serializer = new XmlSerializer(typeof(SaveObject));
using (TextWriter writer = new StreamWriter(FilePath))
{
serializer.Serialize(writer, SO);
}
}
else // auto save !
{
XmlSerializer serializer = new XmlSerializer(typeof(SaveObject));
using (TextWriter writer = new StreamWriter(@"C:'Users'user'Desktop'MapSample'bin'Debug'AutoSave.xml"))
{
serializer.Serialize(writer, SO);
}
}
}
希望它能在某个时候帮助任何人。享受。:)
如果您有 2 个列表并以这种方式执行此操作(错误)
var serializer = new XmlSerializer(typeof(List<Observer>));
using (var writer = new StreamWriter(@"C:'Users'user'Desktop'MapSample'bin'Debug'ListObserver.xml"))
serializer.Serialize(writer, listA);
using (var writer = new StreamWriter(@"C:'Users'user'Desktop'MapSample'bin'Debug'ListObserver.xml"))
serializer.Serialize(writer, listB);
然后listB
将覆盖ListObserver.xml
内容。
你可以试试这个
var serializer = new XmlSerializer(typeof(List<List<Observer>>));
using (var writer = new StreamWriter(@"C:'Users'user'Desktop'MapSample'bin'Debug'ListObserver.xml"))
serializer.Serialize(writer, new List<List<Observer>>(new[] {listA, listB}));
如果它不起作用(无论出于何种原因),则只需创建序列化对象
public class SerializationObject
{
public List<Observer> ListA {get; set;}
public List<Observer> ListB {get; set;}
}
并使用它
var serializer = new XmlSerializer(typeof(SerializationObject));
using (var writer = new StreamWriter(@"C:'Users'user'Desktop'MapSample'bin'Debug'ListObserver.xml"))
serializer.Serialize(writer, new SerializationObject() { ListA = listA, ListB = listB });