Custom Zedgraph ToolStripMenuItem赢得';t单击时进行检查
本文关键字:单击 进行检查 Zedgraph ToolStripMenuItem 赢得 Custom | 更新日期: 2023-09-27 18:24:19
由于以下原因,我自定义了右键菜单:
lineGraphControl1.ContextMenuBuilder += new ZedGraphControl.ContextMenuBuilderEventHandler(MyContextMenuBuilder);
和
private void MyContextMenuBuilder(ZedGraphControl control, ContextMenuStrip menuStrip, Point mousePt, ZedGraphControl.ContextMenuObjectState objState)
{
// create a new menu item
ToolStripMenuItem item = new ToolStripMenuItem();
// This is the user-defined Tag so you can find this menu item later if necessary
item.Name = "simple_cursor";
// This is the text that will show up in the menu
item.Text = "Simple Cursor";
item.CheckOnClick = true;
// Add a handler that will respond when that menu item is selected
item.Click += new System.EventHandler(DisplaySimpleCursor);
// Add the menu item to the menu
menuStrip.Items.Add(item);
}
但单击菜单Simple Cursor
时不会进行检查。我试图在函数DisplaySimpleCursor()
中强制发送方,但它不起作用。
当我调试我的应用程序时,我看到在DisplaySimpleCursor()
中,发件人的属性Checked设置为true。
我错过了什么?
由于菜单是在高温下构建的,checkOnClick
没有任何意义,因为每次隐藏菜单时对象都会被破坏(我想)。
解决方案是设置属性:
// showOneCursor is a bool describing my need and toggled on click
item.Checked = showOneCursor;
试试这个。
private bool check;
public bool Check
{
get { return check; }
set { check= value; }
}
private void MyContextMenuBuilder(ZedGraphControl control, ContextMenuStrip menuStrip, Point mousePt, ZedGraphControl.ContextMenuObjectState objState)
{
ToolStripMenuItem item = new ToolStripMenuItem();
item.Name = "simple_cursor";
item.Text = "Simple Cursor";
item.CheckOnClick = true;
item.Checked = Check; //add this
item.Click += new System.EventHandler(DisplaySimpleCursor);
menuStrip.Items.Add(item);
}
private void DisplaySimpleCursor(object sender, EventArgs e)
{
Check = false==Check;
}