C#MVC3中的复杂URL
本文关键字:URL 复杂 C#MVC3 | 更新日期: 2023-09-27 18:24:36
我是MVC3的新手,无法解决此问题。我正在用帖子做一个简单的博客,这些帖子被分为几个类别,每个帖子可能都有一些标签。若我向用户显示帖子,那个么我就在那个里进行分页,url类似于localhost/posts/1,其中"1"是页码。但是,如果我只想显示来自某个类别或带有某个标签的帖子,我该怎么做呢?它的格式为localhost/Posts/Categories/1,其中"1"是类别的id,或者localhost/Posts/Tags/tag1,其中"tag1"是特定的标签我想将其全部更改为localhost/Posts/Page/1或localhost/Posts/Categories/1/Page/1或localhost/Posts/Tags/tag1/Page/1格式,但我真的找不到如何在控制器中实现这一点。所以我的问题是:如何在控制器中创建方法来接受这些复杂的url?
我想这与路由有关,但找不到任何关于我问题的解释。
非常感谢你的帮助。
我的代码:
public ActionResult Tags(string id)
{
Tag tag = GetTag(id);
ViewBag.IdUser = IDUser;
if (IDUser != -1)
{
ViewBag.IsAdmin = IsAdmin;
ViewBag.UserName = model.Users.Where(x => x.IDUser == IDUser).First().Name;
}
return View("Index", tag.Posts.OrderByDescending(x => x.DateTime));
}
public ActionResult Index(int? id)
{
int pageNumber = id ?? 0;
IEnumerable<Post> posts =
(from post in model.Posts
where post.DateTime < DateTime.Now
orderby post.DateTime descending
select post).Skip(pageNumber * PostsPerPage).Take(PostsPerPage + 1);
ViewBag.IsPreviousLinkVisible = pageNumber > 0;
ViewBag.IsNextLinkVisible = posts.Count() > PostsPerPage;
ViewBag.PageNumber = pageNumber;
ViewBag.IdUser = IDUser;
if (IDUser != -1)
{
ViewBag.IsAdmin = IsAdmin;
ViewBag.UserName = model.Users.Where(x => x.IDUser == IDUser).First().Name;
}
return View(posts.Take(PostsPerPage));
}
创建新的路由,将这些URL模式引导到您的控制器(或另一个控制器,视情况而定)
http://www.asp.net/mvc/tutorials/older-versions/controllers-and-routing/asp-net-mvc-routing-overview-cs
例如,此路线定义
routes.MapRoute(
"CategoryPage", // Route name
"Posts/Categories/{CategoryID}/Page/{PageID}", // URL with parameters
new { controller = "Home", action = "ViewPage", CategoryID = "", PageID="" } // Parameter defaults
);
将被HomeController中的此操作拾取:
public ActionResult ViewPage(int CategoryID, int PageID)