在方法中传递参数,在if-else语句C#中传递参数
本文关键字:参数 语句 方法 if-else | 更新日期: 2023-09-27 18:24:48
我正在编写一个方法,该方法可以接受一定数量的参数,并包含一个if-else语句。当我使用命令行参数时,我会传入至少3个参数,最多4个参数。
当我只使用3个参数运行命令行时,它应该只运行if的第一部分。只有当我必须传递第四个参数时,它才会运行else,但每次我运行四个参数,代码都不会到达else,只运行if语句的开头。任何想法都值得赞赏
protected void net_group(string command, string param1, string param2, string param3)
{
Console.WriteLine("Got information net group command");
//creates group.txt file when "net group" command is used
string path = "C:''Files''groups.txt";
using (StreamWriter sw = File.AppendText(path))
{
sw.WriteLine(param2 + ": " + param3); //param2 is name of the group //param3 is name of user
}
if (not sure what argument would go here) {
//writes to the audit log and to the console when group is made w/out users
Console.WriteLine("Group " + param2 + " created");
string path2 = "C:''Files''audit.txt";
using (StreamWriter sw2 = File.AppendText(path2))
{
sw2.WriteLine("Group " + param2 + " created");
}
}
else
{
//writes to the audit log and to the console when user is added to a new group
//currently the method wont reach here even when I pass four parameters
Console.WriteLine("User " + param3 + " added to group " + param2 + "");
string path3 = "C:''Files''audit.txt"; //doesnt write this to audit.txt
using (StreamWriter sw3 = File.AppendText(path3))
{
sw3.WriteLine("User " + param3 + " added to group " + param2 + "");
}
}
Console.Read();
查看方法的签名,最好的解决方案是使用以下内容:
if (String.IsNullOrEmpty(param3)) // you could say that only 3 params were given
{
}
else // you could say that all 4 params were given
{
}
看看这个Microsoft教程。
我想你的代码会是这样的:
static void Main(string[] args)
{
...
if (args.Length == 3) {
//writes to the audit log and to the console when group is made w/out users
Console.WriteLine("Group " + args[1] + " created");
string path2 = "C:''Files''audit.txt";
using (StreamWriter sw2 = File.AppendText(path2))
{
sw2.WriteLine("Group " + args[1] + " created");
}
}
else
{
//writes to the audit log and to the console when user is added to a new group
正如教程所指出的,您还可以使用Environment.CommandLine或Environment.GetCommandLineArgs从控制台或Windows应用程序中的任何点访问命令行参数。