12小时制，十进制的第12小时

本文关键字：12小时 十进制 | 更新日期: 2023-09-27 18:25:32

我有一个12小时的时钟，可以用十进制计算两次之间的差值。它在下面的循环中运行，但经过测试，我发现当我输入12:00到12:59（上午或下午）之间的时间时，它发布的时间完全错误。问题是，第12个小时是一种特殊情况，不需要添加或减去12。我如何解决这个问题，使其以十进制形式显示正确的时间？

此外，由于我发布了这篇文章，我还有另一个问题；我怎样才能容易地用十进制计算总时间？

下面是GUI的图片，这样您就可以了解我们正在处理的内容。http://imgur.com/y7JezcC

protected void CalculateButton_Click(object sender, EventArgs e)
{
    //Initializing
    TextBox[] textboxesIn = new TextBox[7];
    TextBox[] textboxesOut = new TextBox[7];
    DropDownList[] dropdownIn = new DropDownList[7];
    DropDownList[] dropdownOut = new DropDownList[7];
    Label[] labels = new Label[7];
    //Week 1 in textboxes
    textboxesIn[0] = MondayW1InTextBox;
    textboxesIn[1] = TuesdayW1InTextBox;
    textboxesIn[2] = WednesdayW1InTextBox;
    textboxesIn[3] = ThursdayW1InTextBox;
    textboxesIn[4] = FridayW1InTextBox;
    textboxesIn[5] = SaturdayW1InTextBox;
    textboxesIn[6] = SundayW1InTextBox;
    //Week 1 out textboxes
    textboxesOut[0] = MondayW1OutTextBox;
    textboxesOut[1] = TuesdayW1OutTextBox;
    textboxesOut[2] = WednesdayW1OutTextBox;
    textboxesOut[3] = ThursdayW1OutTextBox;
    textboxesOut[4] = FridayW1OutTextBox;
    textboxesOut[5] = SaturdayW1OutTextBox;
    textboxesOut[6] = SundayW1OutTextBox;
    //Week 1 in drop down list
    dropdownIn[0] = MondayW1InDropDown;
    dropdownIn[1] = TuesdayW1InDropDown;
    dropdownIn[2] = WednesdayW1InDropDown;
    dropdownIn[3] = ThursdayW1InDropDown;
    dropdownIn[4] = FridayW1InDropDown;
    dropdownIn[5] = SaturdayW1InDropDown;
    dropdownIn[6] = SundayW1InDropDown;
    //Week 1 out drop down list
    dropdownOut[0] = MondayW1OutDropDown;
    dropdownOut[1] = TuesdayW1OutDropDown;
    dropdownOut[2] = WednesdayW1OutDropDown;
    dropdownOut[3] = ThursdayW1OutDropDown;
    dropdownOut[4] = FridayW1OutDropDown;
    dropdownOut[5] = SaturdayW1OutDropDown;
    dropdownOut[6] = SundayW1OutDropDown;
    //Week 1 labels
    labels[0] = MondayW1Label;
    labels[1] = TuesdayW1Label;
    labels[2] = WednesdayW1Label;
    labels[3] = ThursdayW1Label;
    labels[4] = FridayW1Label;
    labels[5] = SaturdayW1Label;
    labels[6] = SundayW1Label;
    for (int i = 0; i < 7; i++)
    {
        DateTime dt = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        string timestring = dt.ToString("h:mm");
        labels[i].Text = timestring;
        DateTime timeIn = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        DateTime timeOut = DateTime.ParseExact(textboxesOut[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        if (dropdownIn[i].SelectedValue == "PM")
        {
            timeIn = timeIn.AddHours(12);
        }
        if (dropdownOut[i].SelectedValue == "PM")
        {
            timeOut = timeOut.AddHours(12);
        }
        labels[i].Text = (timeOut - timeIn).TotalHours.ToString("f2");
    }
}

12小时制，十进制的第12小时

尝试

DateTime timeIn = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0') + dropdownIn[i].SelectedValue.Text, "hhmm tt", CultureInfo.InvariantCulture);

您必须将HH更改为HH，因为您无法将12AM解析为HH。之后，您可以毫无问题地超时-超时。

在任何情况下，当你写1到11时，默认情况下都是AM，你可以求和12 hs，但当你写12时，总是PM（AM是00），所以：

下午1点+12=13

下午2点+12=14

晚上11点+12=23

//现在你奇怪的结果：

12:45（下午）+12=24:45=>00:45但后一天

下午3:00+12=15

15hs（第0天）-00:45（第1天）是您的阴性结果。

一个简单的方法是在12小时的情况下休息12小时。

for (int i = 0; i < 7; i++)
    {
        DateTime dt = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        string timestring = dt.ToString("h:mm");
        labels[i].Text = timestring;
        DateTime timeIn = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        DateTime timeOut = DateTime.ParseExact(textboxesOut[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        if(timeIn.Hour == 12) timeIn = timeIn.AddHours(-12);  //a easy way
        if (dropdownIn[i].SelectedValue == "PM")
        {
            timeIn = timeIn.AddHours(12);
        }
        if (dropdownOut[i].SelectedValue == "PM")
        {
            timeOut = timeOut.AddHours(12);
        }
        labels[i].Text = (timeOut - timeIn).TotalHours.ToString("f2");
    }
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