POST don';不起作用
本文关键字:不起作用 don POST | 更新日期: 2023-09-27 18:25:44
all!我有这样的php页面:
<?php
if(isset($_POST['userid']) and isset($_POST['dlspeed']) )
{
$userid=$_POST['userid'];
$dlspeed=$_POST['dlspeed'];
$timestamp =date("y-m-d H:i");
$db_conn = mysql_connect('localhost', "root", "asdk78623r");
mysql_select_db("speedtest", $db_conn);
$query='INSERT INTO status VALUE (NULL, "'.$userid.'", "'.$dlspeed.'", "'.$timestamp.'")';
$result=mysql_query($query,$db_conn);
}
?
从C#我做的帖子:
HttpWebRequest WebReq = (HttpWebRequest)WebRequest.Create(pageurl);
byte[] buffer = Encoding.ASCII.GetBytes(data);
System.Net.ServicePointManager.Expect100Continue = false;
WebReq.SendChunked = false;
WebReq.Expect = null;
WebReq.KeepAlive = false;
//I try also setting proxy
// WebReq.Proxy = new WebProxy("192.168.0.107", 3128);
//Our method is post, otherwise the buffer (postvars) would be useless
WebReq.Method = "POST";
//We use form contentType, for the postvars.
WebReq.ContentType = "application/x-www-form-urlencoded";
//The length of the buffer (postvars) is used as contentlength.
WebReq.ContentLength = buffer.Length;
//We open a stream for writing the postvars
Stream PostData = WebReq.GetRequestStream();
//Now we write, and afterwards, we close. Closing is always important!
PostData.Write(buffer, 0, buffer.Length);
PostData.Close();
//posted data is not inserted in db
//and in follow line code Ive got error: The remote server returned an error: (417) //Expectation failed
HttpWebResponse WebResp = (HttpWebResponse)WebReq.GetResponse();
我做错了什么?使用follow curl命令站工作正常:
curl -d "userid=SW783IC2QDHFYU6P4XKO&dlspeed=814,602968463903×tamp=2012-2-23 19:29:33" pageurl
有什么想法、建议、重新考虑吗?
发生这种情况的原因有多种选择。
http://www.checkupdown.com/status/E417.html
其中一个原因可能是:http://haacked.com/archive/2004/05/15/http-web-request-expect-100-continue.aspx
安装一个程序,记录你的请求和它们包含的内容(fiddler2工作得很好,免费且易于使用,有几个非常相似但记不起它们的名字atm)
试着看看你是否找到了不应该出现的标题,如果你一辈子都找不到,一旦你发布了,这里的人可能会帮助你。