字典有两个键

本文关键字：两个 字典 | 更新日期: 2023-09-27 18:25:49

我正在跟踪控制台中的值。两个人互相"决斗"，我用字典把名字和造成的伤害一起记录下来。

var duels = new Dictionary<string, string>();
duels.Add("User1", "50");
duels.Add("User2","34");

我试图将两个用户存储在同一个字典行中，这样就可以验证为User1正在与User2决斗。这样，如果另一场决斗开始，它就不会干扰User1或User2。

duels.Add("KeyUser1","KeyUser2","50","34",.../*Other attributes of the duel*/);

我需要两把钥匙，这样我就可以检查用户的损坏情况。损坏总是发生在另一把钥匙上，反之亦然。我该怎么做才能让它发挥作用？

谢谢。

字典有两个键

public class Duel
{
  public string User1 {get; protected set;}
  public string User2 {get; protected set;}
  public Duel(string user1, string user2)
  {
    User1 = user1;
    User2 = user2;
  }
  public HashSet<string> GetUserSet()
  {
    HashSet<string> result = new HashSet<string>();
    result.Add(this.User1);
    result.Add(this.User2);
    return result;
  }
  //TODO ... more impl
}

让我们决斗吧。CreateSetComparer允许字典使用集合的值进行相等性测试。

List<Duel> duelSource = GetDuels();
Dictionary<HashSet<string>, Duel> duels =
  new Dictionary<HashSet<string>, Duel>(HashSet<string>.CreateSetComparer());
foreach(Duel d in duelSource)
{
  duels.Add(d.GetUserSet(), d);
}

寻找决斗：

HashSet<string> key = new HashSet<string>();
key.Add("User1");
key.Add("User2");
Duel myDuel = duels[key];

您可以尝试为密钥创建一个自定义数据类型：

class DualKey<T> : IEquatable<DualKey<T>> where T : IEquatable<T>
{
    public T Key0 { get; set; }
    public T Key1 { get; set; }
    public DualKey(T key0, T key1)
    {
        Key0 = key0;
        Key1 = key1;
    }
    public override int GetHashCode()
    {
        return Key0.GetHashCode() ^ Key1.GetHashCode();
    }
    public bool Equals(DualKey<T> obj)
    {
        return (this.Key0.Equals(obj.Key0) && this.Key1.Equals(obj.Key1))
            || (this.Key0.Equals(obj.Key1) && this.Key0.Equals(obj.Key0));
    }
}

然后使用Dictionary<DualKey<string>, string>；

一些快速的东西。

class UserScores {
    public string Key { get; set; }
    public int User1Score { get; set; }
    public int User2Score { get; set; }
    public UserScores(string username1, string username2)
    {
            Key = username1 + ":" + username2;
    }
}
void Main()
{
    var userScore = new UserScores("fooUser", "barUser");
    var scores = new Dictionary<string, UserScores>();
    scores.Add(userScore.Key, userScore);
    // Or use a list
    var list = new List<UserScores>();
    list.Add(userScore);
    list.Single (l => l.Key == userScore.Key);
}

尽管在我看来，一个合适的解决方案是使用一个经过深思熟虑的UserScores对象来跟踪特定的"决斗"会话。

由于一个人一次最多只能参与一场决斗，因此您可以使用一个字典在所有决斗中直接"索引"两个端点，类似于以下内容：

class Duel {
    public Duel(string user1, string user2) {
        Debug.Assert(user1 != user2);
        User1 = user1;
        User2 = user2;
    }
    public readonly string User1;
    public readonly string User2;
    public int User1Score;
    public int User2Score;
}
class Program {
    static void Main(string[] args) {
        var dict = new Dictionary<string, Duel>();
        // Add a new duel. A single duel has two keys in the dictionary, one for each "endpoint".
        var duel = new Duel("Jon", "Rob");
        dict.Add(duel.User1, duel);
        dict.Add(duel.User2, duel);
        // Find Jon's score, without knowing in advance whether Jon is User1 or User2:
        var jons_duel = dict["Jon"];
        if (jons_duel.User1 == "Jon") {
            // Use jons_duel.User1Score.
        }
        else {
            // Use jons_duel.User2Score.
        }
        // You can just as easily find Rob's score:
        var robs_duel = dict["Rob"];
        if (robs_duel.User1 == "Rob") {
            // Use robs_duel.User1Score.
        }
        else {
            // Use robs_duel.User2Score.
        }
        // You are unsure whether Nick is currently duelling:
        if (dict.ContainsKey("Nick")) {
            // Yup!
        }
        else {
            // Nope.
        }
        // If Jon tries to engage in another duel while still duelling Rob:
        var duel2 = new Duel("Jon", "Nick");
        dict.Add(duel2.User1, duel); // Exception! Jon cannot be engaged in more than 1 duel at a time.
        dict.Add(duel2.User2, duel); // NOTE: If exception happens here instead of above, don't forget remove User1 from the dictionary.
        // Removing the duel requires removing both endpoints from the dictionary:
        dict.Remove(jons_duel.User1);
        dict.Remove(jons_duel.User2);
        // Etc...
    }
}

这只是一个基本想法，您可以考虑将此功能封装在自己的类中。。。

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