像 Python 的集合这样的库.C# 的计数器库 -> 获取 C# 中两个字典对象之间的值差异
本文关键字:字典 两个 对象 之间 获取 集合 Python 计数器 | 更新日期: 2023-09-27 18:32:59
这就是我在C#中创建字典的方式。
Dictionary<string, int> d = new Dictionary<string, int>()
{
{"cheese", 2},
{"cakes", 1},
{"milk", 0},
{"humans", -1} // This one's for laughs
};
在 Python 中,如果你有这样的字典:
from collections import Counter
my_first_dict = {
"cheese": 1,
"cakes": 2,
"milk": 3,
}
my_second_dict = {
"cheese": 0,
"cakes": 1,
"milk": 4,
}
print Counter(my_first_dict) - Counter(my_second_dict)
>>> Counter({'cheese': 1, 'cakes': 1})
如您所见,Counter
在比较字典对象时非常有用。
C# 中是否有一个库,可以让我做类似的事情,还是我必须从头开始编码?
您可以将两个字典连接在一起,然后仅使用几行代码根据给定操作创建一个新字典:
Dictionary<string, int> d1 = new Dictionary<string, int>();
Dictionary<string, int> d2 = new Dictionary<string, int>();
var difference = d1.Join(d2, pair => pair.Key, pair => pair.Key, (a, b) => new
{
Key = a.Key,
Value = a.Value - b.Value,
})
.Where(pair => pair.Value > 0)
.ToDictionary(pair => pair.Key, pair => pair.Value);
您已经展示过没有包装字典的系统类,并为它们提供了-
运算符,但是如果您愿意,您可以轻松创建自己的系统类:
public class Counter<T> : IEnumerable<KeyValuePair<T, int>>
{
private IEnumerable<KeyValuePair<T, int>> sequence;
public Counter(IEnumerable<KeyValuePair<T, int>> sequence)
{
this.sequence = sequence;
}
public static Counter<T> operator -(Counter<T> first, Counter<T> second)
{
return new Counter<T>(first.Join(second
, pair => pair.Key, pair => pair.Key, (a, b) =>
new KeyValuePair<T, int>(a.Key, a.Value - b.Value))
.Where(pair => pair.Value > 0));
}
public IEnumerator<KeyValuePair<T, int>> GetEnumerator()
{
return sequence.GetEnumerator();
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
没有这样的内置功能,但您可以使用一些 Linq:
Dictionary<string, int> first = new Dictionary<string, int>()
{
{"cheese", 1},
{"cakes", 2},
{"milk", 3},
};
Dictionary<string, int> second = new Dictionary<string, int>()
{
{"cheese", 0},
{"cakes", 1},
{"milk", 4},
};
var results =
(from x in first
join y in second on x.Key equals y.Key
where x.Value - y.Value > 0
select new { x.Key, Value = x.Value - y.Value })
.ToDictionary(p => p.Key, p => p.Value);
// returns a dictionary like { { "cheese", 1 }, { "cakes", 1 } }