Initialize a ViewDataDictionary
本文关键字:ViewDataDictionary Initialize | 更新日期: 2023-09-27 18:26:12
我需要构建一个函数,该函数接受一个参数并将其传递给System.Web.Mvc.ViewDataDictionary
构造函数。这是我的代码:
// this WORKS, but need to pass as parameter
var dic1 = new System.Web.Mvc.ViewDataDictionary { { "key", "value" } };
// this DOES NOT WORK
Test({ "key", "value" }); // I try do not have 'new Something({"", ""})'
function Test(object myParam) {
var dic2 = new System.Web.Mvc.ViewDataDictionary { myParam };
//...
}
有没有一种方法可以像我一样传递参数,而不需要传递整个new System.Web.Mvc.ViewDataDictionary { { "key", "value" } }
作为Test
函数的参数?
PS这是解释问题的一些测试代码
// WORKS
var dic1 = new System.Web.Mvc.ViewDataDictionary { { "key", "value" } };
// DOES NOT WORK
// A CASE
string[] myArr = { "key", "value" }; // OK
var dic2 = new System.Web.Mvc.ViewDataDictionary { myArr }; // NOK
// B CASE
KeyValuePair<string, object> myPair = {"key", "value"}; // NOK
var dic3 = new System.Web.Mvc.ViewDataDictionary { myPair }; // OK
PPS。多参数案例:
// WORKS
var dic1 = new ViewDataDictionary { { "key", "value" }, {"key2", "value2"} };
var dic2 = new ViewDataDictionary { (replace w/ one single obj/arr impossible?)};
遗憾的是,由于花括号只能用于集合初始化,因此无法实现您想要的结果。只有当这些花括号连接到new
关键字时,解析器才会以特殊的方式处理这些花括号。它解析它们并生成一组Add
调用。
如果你只想传递密钥和值,可以这样做:
Test("key", "value");
void Test(string key, object value) {
var dic2 = new ViewDataDictionary { { key, value } };
//...
}
ViewDataDictionary
包含一个接受另一个ViewDataDictionary
:的构造函数
Test(new ViewDataDictionary { { key, value } });
void Test(ViewDataDictionary dictionary) {
var dic2 = new ViewDataDictionary(dictionary);
//...
}
如果您需要将一些值从一个ViewDataDictionary
添加到另一个现有的ViewDataDictionary
,您可以使用以下代码:
Test(new ViewDataDictionary { { key, value } });
void Test(ViewDataDictionary dictionary) {
var dic2 = new ViewDataDictionary();
// ... initialize dic2
foreach (var pair in dictionary)
{
dic2.Add(pair);
}
}
如果需要传递(KeyValuePair
元素的)数组来初始化字典,可以通过以下方式完成:
Test(new[] { new KeyValuePair<string, object>("key1", "value1"),
new KeyValuePair<string, object>("key2", "value2") });
void Test(KeyValuePair<string, object>[] pairs) {
var dic2 = new ViewDataDictionary();
foreach (var pair in pairs)
{
dic2.Add(pair);
}
//...
}