我怎样才能选择一张唱片而不是另一张

本文关键字:一张 唱片 选择 | 更新日期: 2023-09-27 18:26:25

我有一个列表,其中有一些重复项。

Row#    Lineid  ItemDescItemId  RoadTax VehicleId   Amount
1   122317  None    -1  26.63   -78603  300
2   122317  None    -2  17.75   -78603  200
3   122317  None    -1  22.19   -78602  250
4   122317  Deli    -2  17.75   -78603  200

在这种情况下,行2是行4的副本,因为LineId、RoadTaxy、Amount和VehicleId匹配。但是,我想保留带有项目描述的行,并删除第2行。所以我的输出列表如下:

Row#    Lineid  ItemDesc ItemId RoadTax VehicleId   Amount
1   122317  None    -1  26.63   -78603  300
3   122317  None    -1  22.19   -78602  250
4   122317  Deli    -2  17.75   -78603  200

我根据MSDN上的一个例子编写了一个IEqualityComparer类。类看起来是这样的:

  public class RoadTaxComparer : IEqualityComparer<RoadTaxDto>
        {
            // Items are equal if ItemId / VehicleId / RoadTax are equal.
            public bool Equals(RoadTaxDto x, RoadTaxDto y)
            {
                //Check whether the compared objects reference the same data. 
                if (Object.ReferenceEquals(x, y)) return true;
                //Check whether any of the compared objects is null. 
                if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null))
                    return false;
                //Check whether the products' properties are equal. 
                return x.VehicleId == y.VehicleId && x.ItemId == y.ItemId && x.RoadTax == y.RoadTax && x.Amount == y.Amount;
            }
            // If Equals() returns true for a pair of objects  
            // then GetHashCode() must return the same value for these objects. 
            public int GetHashCode(RoadTaxDto roadTaxDto)
            {
                //Check whether the object is null 
                if (Object.ReferenceEquals(roadTaxDto, null)) return 0;
                //Get hash code for the VehicleId. 
                int hashVehicleId = roadTaxDto.VehicleId.GetHashCode();
                //Get hash code for the ItemId field. 
                int hashCodeItemId = roadTaxDto.ItemId.GetHashCode();
                //Calculate the hash code for the QuoteTaxDto. 
                return hashVehicleId ^ hashCodeItemId;
            }
        }

RoadTaxDto结构如下:

class RoadTaxDto
{
public int LineId {get;set}
public string ItemDesc {get;set;}
public int VehicleId {get;set;}
public decimal RoadTax {get;set;}
public int VehicleId {get;set;}
public decimal Amount {get;set;}
}

我使用以下命令来消除重复。

List<RoadTaxDto> mergedList = RoadTaxes.Union(RoadTaxes, new RoadTaxComparer()).ToList();

当我在上面运行比较器时,我不能保证第2行被消除。那么,我如何确保如果一个记录有重复项,那么写着"无"的记录总是会从列表中删除呢。

我怎样才能选择一张唱片而不是另一张

我会将GetHashCode()移动到RoadTaxDto,然后执行以下操作:

foreach (var g in list.GroupBy(i => i.GetHashCode()))
    list2.Add(
        g.FirstOrDefault(i => i.ItemDesc != "None") ?? 
        g.First());

纯"SQLish"方法对您不起作用?

类似这样的东西:

var list = new [] { 
    new RoadTaxDto {LineId=122317,ItemDesc="None", ItemId=-1,RoadTax =26.63M  , VehicleId=-78603  ,Amount=300},
    new RoadTaxDto {LineId=122317,ItemDesc="None", ItemId=-2,RoadTax =17.75M  , VehicleId=-78603  ,Amount=200},
    new RoadTaxDto {LineId=122317,ItemDesc="None", ItemId=-1,RoadTax =22.19M  , VehicleId=-78602  ,Amount=250},
    new RoadTaxDto {LineId=122317,ItemDesc="Deli", ItemId=-2,RoadTax =17.75M , VehicleId=-78603  ,Amount=200}
};
var query = (from c in list join x in list 
    on new { c.LineId, c.ItemId , c.VehicleId, c.Amount,c.RoadTax} 
equals new {x.LineId, x.ItemId, x.VehicleId,x.Amount,x.RoadTax}
select new RoadTaxDto {
   LineId = c.LineId,
   ItemDesc = x.ItemDesc!="None"? x.ItemDesc:c.ItemDesc,
   VehicleId=c.VehicleId,
   Amount=c.Amount,
   RoadTax=c.RoadTax,
   ItemId=c.ItemId
}
).GroupBy(x => new { x.LineId, x.RoadTax, x.Amount, x.VehicleId} )
 .Select(grp => grp.Last());

打印:

LineId  ItemDesc    VehicleId   ItemId  RoadTax Amount
122317  None        -78603      -1      26.63   300
122317  Deli        -78603      -2      17.75   200
122317  None        -78602      -1      22.19   250