在c#中通过反序列化将xml转换为列表
本文关键字:xml 转换 列表 反序列化 | 更新日期: 2023-09-27 17:54:24
我有一个XML文件,我正试图通过反序列化填充我的数据列表。
我的XML在这里
<?xml version="1.0" ?>
<CustomerQueryRs>
<CustomerRet>
<ListID>6BE0000-1159990808</ListID>
<Name>+ Blaine Bailey</Name>
<FullName>+ Blaine Bailey</FullName>
<Phone>866-855-0800</Phone>
</CustomerRet>
<CustomerRet>
<ListID>9BA0000-1165353294</ListID>
<Name>+ Brian Boyd</Name>
<FullName>+ Brian Boyd</FullName>
<Phone>203-245-1877</Phone>
</CustomerRet>
<CustomerRet>
<ListID>9280000-1164147562</ListID>
<Name>+ Brian Leahy</Name>
<FullName>+ Brian Leahy</FullName>
<Phone>508-341-0955</Phone>
</CustomerRet>
</CustomerQueryRs>
这里我给出了我的完整代码。我只是不明白为什么我的代码不工作…我的代码中缺少什么......它没有给出错误,但列表没有被填充。所以请告诉我代码中哪些地方需要修改
[XmlTypeAttribute(AnonymousType = true)]
public class CustomersData
{
[XmlArray(ElementName = "CustomerQueryRs")]
[XmlArrayItem(ElementName = "CustomerRet")]
public List<Customer> Customers { get; set; }
public CustomersData()
{
Customers = new List<Customer>();
}
}
public class Customer
{
[XmlElement(ElementName = "ListID")]
public string ListID { get; set; }
[XmlElement(ElementName = "Name")]
public string Name { get; set; }
[XmlElement(ElementName = "FullName")]
public string FullName { get; set; }
[XmlElement(ElementName = "Phone")]
public string Phone { get; set; }
}
这是我的反序列化代码
private object DeserialzeXml(string xml)
{
var xmlSer = new XmlSerializer(typeof(CustomersData), new XmlRootAttribute("CustomerQueryRs"));
var stringReader = new StringReader(xml);
return xmlSer.Deserialize(stringReader);
}
请帮…
应该可以:
[XmlElement("CustomerRet")]
public List<Customer> Customers { get; set; }
和一个完整的例子:
[XmlTypeAttribute(AnonymousType = true)]
public class CustomersData
{
[XmlElement("CustomerRet")]
public List<Customer> Customers { get; set; }
public CustomersData()
{
Customers = new List<Customer>();
}
}
public class Customer
{
[XmlElement(ElementName = "ListID")]
public string ListID { get; set; }
[XmlElement(ElementName = "Name")]
public string Name { get; set; }
[XmlElement(ElementName = "FullName")]
public string FullName { get; set; }
[XmlElement(ElementName = "Phone")]
public string Phone { get; set; }
}
class Program
{
static void Main()
{
var xml =
@"<?xml version=""1.0"" ?>
<CustomerQueryRs>
<CustomerRet>
<ListID>6BE0000-1159990808</ListID>
<Name>+ Blaine Bailey</Name>
<FullName>+ Blaine Bailey</FullName>
<Phone>866-855-0800</Phone>
</CustomerRet>
<CustomerRet>
<ListID>9BA0000-1165353294</ListID>
<Name>+ Brian Boyd</Name>
<FullName>+ Brian Boyd</FullName>
<Phone>203-245-1877</Phone>
</CustomerRet>
<CustomerRet>
<ListID>9280000-1164147562</ListID>
<Name>+ Brian Leahy</Name>
<FullName>+ Brian Leahy</FullName>
<Phone>508-341-0955</Phone>
</CustomerRet>
</CustomerQueryRs>";
var serializer = new XmlSerializer(typeof(CustomersData), new XmlRootAttribute("CustomerQueryRs"));
using (var stringReader = new StringReader(xml))
using (var reader = XmlReader.Create(stringReader))
{
var result = (CustomersData)serializer.Deserialize(reader);
Console.WriteLine(result.Customers[1].FullName);
}
}
}
将xml转换为列表的可读代码
string xmlString = System.IO.File.ReadAllText(@"C:'Users'user'Downloads'userDetail.xml");
List<GridViewDetails> userDetail = (List<GridViewDetails>)ConvertXmlStringtoObject<List<GridViewDetails>>(xmlString);
static T ConvertXmlStringtoObject<T>(string xmlString)
{
T classObject;
XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));
using (StringReader stringReader = new StringReader(xmlString))
{
classObject = (T)xmlSerializer.Deserialize(stringReader);
}
return classObject;
}