按数值、字母值和符号对列表进行排序
本文关键字:列表 排序 符号 | 更新日期: 2023-09-27 18:27:35
嗨,我一直在绞尽脑汁想办法做到这一点,但我做不到。假设我有以下列表:
1
2
'
@
r
r2
r1
我希望它按以下顺序排序
1
2
r
r1
r2
'
@
我有以下代码(不知道最后在哪里进行符号排序)
void Main()
{
List<string> list = new List<string>();
list.Add("1");
list.Add("2");
list.Add("'");
list.Add("@");
list.Add("r");
list.Add("r2");
list.Add("r1");
list.Sort(new AlphanumComparatorFastString());
}
public class AlphanumComparatorFastString : IComparer<String>
{
public int Compare(string s1, string s2)
{
if (s1 == null)
return 0;
if (s2 == null)
return 0;
int len1 = s1.Length;
int len2 = s2.Length;
int marker1 = 0;
int marker2 = 0;
// Walk through two the strings with two markers.
while (marker1 < len1 && marker2 < len2)
{
char ch1 = s1[marker1];
char ch2 = s2[marker2];
// Some buffers we can build up characters in for each chunk.
char[] space1 = new char[len1];
int loc1 = 0;
char[] space2 = new char[len2];
int loc2 = 0;
// Walk through all following characters that are digits or
// characters in BOTH strings starting at the appropriate marker.
// Collect char arrays.
do
{
space1[loc1++] = ch1;
marker1++;
if (marker1 < len1)
{
ch1 = s1[marker1];
}
else
{
break;
}
} while (char.IsDigit(ch1) == char.IsDigit(space1[0]));
do
{
space2[loc2++] = ch2;
marker2++;
if (marker2 < len2)
{
ch2 = s2[marker2];
}
else
{
break;
}
} while (char.IsDigit(ch2) == char.IsDigit(space2[0]));
// If we have collected numbers, compare them numerically.
// Otherwise, if we have strings, compare them alphabetically.
string str1 = new string(space1);
string str2 = new string(space2);
int result;
if (char.IsDigit(sp`enter code here`ace1[0]) && char.IsDigit(space2[0]))
{
int thisNumericChunk = int.Parse(str1);
int thatNumericChunk = int.Parse(str2);
result = thisNumericChunk.CompareTo(thatNumericChunk);
}
else
{
result = str1.CompareTo(str2);
}
if (result != 0)
{
return result;
}
}
return len1 - len2;
}
}
Thanks for the help
var ordered = list.OrderByDescending(x => x.All(char.IsDigit))
.ThenByDescending(x=> x.Any(char.IsLetter))
.ThenBy(x=>x)
.ToList();
结果:
1
2
r
r1
r2
'
@
我会拆分你的逻辑
var list = new List<string>{"1", "2", "'", "@", "r", "r2", "r1"};
//Process the list into segments/classes for ordering
var ordered = list
.Select(d => new { OrderBy = GetOrderByClass(d), Value = d })
.OrderBy(d => d.OrderBy)
.ThenBy(d => d.Value)
.Select(d => d.Value)
.ToList();
//Get's a segment/class against an input type
public int GetOrderByClass(string value)
{
//Numbers
if(Regex.IsMatch(value, "$''d+"))
return 0;
//Alpha
if(Regex.IsMatch(value, "[a-zA-Z0-9]+"))
return 1;
//Everything else
return 2;
}
循环s1和s2的所有字符,直到得到两个不同的字符
-如果所有字符都相同,则返回0。
比较2个字符
-如果它们是不同的类型(数字、字符、字母),则比较类型
-如果它们是相同的类型,则比较字符